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kolezko [41]
3 years ago
14

Using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuri

es.
Physics
2 answers:
Ludmilka [50]3 years ago
3 0
It all has to do with what's going on around us. The speed of the vehicles, the type of vehicle, the safety factors, seatbelts, where you are in the car, what was the force of the impact, etc; Every accident has different factors playing into them in order to lead to said injuries 
WITCHER [35]3 years ago
3 0
Angle of attack ,velocity ,seatbelt health, airbags, cumbustion of the car ,car type, saftey features ,location of  collision aka being hit in the drivers side door is worse then being hit in the trunk
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In an experiment performed in a space station, a force of 60n causes an object to have an acceleration equal to 4m/s s .what is
Troyanec [42]
We Know, F = m*a
Here, F = 60N
a = 4 m/s²

Substitute their values in the equation,
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5 0
3 years ago
A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used
Blizzard [7]

Answer:

a,b)   #_ {electron} = 1.64 10¹⁹ electrons, c)  R = 19.54  Ω, d)   V = 10.3 V

Explanation:

a and b) The current is defined as the number of electrons that pass per unit of time

let's look for the load

            Q = I t

            Q = 0.526  5

            Q = 2.63 C

Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?

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           #_ {electron} = 1.64 10¹⁹ electrons

         

c) the resistance of a wire is given by

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the area of ​​the wire is

           A = π r2 = π d²/4

         

we substitute

            R = \rho \ l \ \frac{4}{\pi  d^2}

let's calculate

           R = 5.6 10⁻⁸  0.580 \frac{4}{ \pi  (0.046 \ 10^{-3})^2 }

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d) let's use ohm's law

           V = i R

            V = 0.526 19.54

            V = 10.3 V

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