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kolezko [41]
3 years ago
14

Using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuri

es.
Physics
2 answers:
Ludmilka [50]3 years ago
3 0
It all has to do with what's going on around us. The speed of the vehicles, the type of vehicle, the safety factors, seatbelts, where you are in the car, what was the force of the impact, etc; Every accident has different factors playing into them in order to lead to said injuries 
WITCHER [35]3 years ago
3 0
Angle of attack ,velocity ,seatbelt health, airbags, cumbustion of the car ,car type, saftey features ,location of  collision aka being hit in the drivers side door is worse then being hit in the trunk
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A 50 kg boy is at the edge of a circular platform of radius 4.0 m which is rotating freely
Flauer [41]

Answer:

0.62 rad/s

Explanation:

Angular momentum is conserved.

I₁ ω₁ = I₂ ω₂

where I is moment of inertia and ω is angular velocity.

The total moment of inertia is the sum of the platform's inertia and the boy's.

(I + m r₁²) ω₁ = (I + m r₂²) ω₂

Given I = 1000 kg m², m = 50 kg, r₁ = 4.0 m, r₂ = 3.0 m, and ω₁ = 0.5 rad/s:

(1000 + 50 (4.0)²) (0.5) = (1000 + 50 (3.0)²) ω₂

900 = 1450 ω₂

ω₂ = 0.62 rad/s

8 0
3 years ago
What is the formula to find how far a wheel travels in one rotation?
alekssr [168]

it is also known as formula for circumfrence which is 2 times pi times radius. if radius was 5 then the circumfrence would be 10pi.

4 0
4 years ago
Deep-sea divers often breathe a mixture of helium and oxygen to avoid getting the "bends" from breathing high-pressure nitrogen.
kvv77 [185]

Answer:

0.69444 m, 0.08152 m, 0.32407 m, 0.03804 m

Explanation:

v = Velocity of sound

f = Frequency

Length of vocal tract is given by

L=\dfrac{v}{4f}

At f = 270 Hz v = 750 m/s

L=\dfrac{750}{4\times 270}\\\Rightarrow L=0.69444\ m

At f = 2300 Hz v = 750 m/s

L=\dfrac{750}{4\times 2300}\\\Rightarrow L=0.08152\ m

At f = 270 Hz v = 350 m/s

L=\dfrac{350}{4\times 270}\\\Rightarrow L=0.32407\ m

At f = 2300 Hz v = 350 m/s

L=\dfrac{350}{4\times 2300}\\\Rightarrow L=0.03804\ m

3 0
3 years ago
A total charge Q is distributed uniformly over a large flat insulating surface of area A . If the electric field magnitude is eq
Andrew [12]

Answer:

a. 1000N/C

Explanation:

Data mentioned in the question

Electrical field magnitude = 1000 NC

Perpendicular distance = 0.1 m

Perpendicular distance = 0.2 m

Based on the above information, the electric field is

As we know that

E = \frac{\sigma}{2\times E_o}

where,

\sigma = surface charge density

E = distance from nearby point to sheet i.e be independent

The distance at 0.1 and 0.2, the electric field would remain the same

So,

Based on the above explanation, the first option is correct

3 0
3 years ago
Suppose that in an alternate universe, the possible values of l are the integer values from 0 to n (instead of 0 to nâ1). assumi
valentina_108 [34]

Answer:

    level     possible values of ℓ     possible values of m     number of orbitals

    n = 1        0, 1                                 -1, 0, 1                                      3

    n = 2       0, 1, 2                             -2, - 1, 0, +1, +2                       5

    n = 3       0, 1, 2, 3                         -3, -2, -1, 0, +1, +2, +3            7    

    n = 4        ...                                    ...                                            9

    n = 5       ...                                    ...                                            11


Explanation:


1. This question is about the quantum numbers: n, ℓ, m, s.


2. n is the principal quantum number, i.e. amin energy level. It can be any positive integer: 1, 2, 3, 4, 5, 6, 7 ...


3. ℓ is the azimuthal quantum number. The possible values of ℓ are from 0 to n - 1.


4. It is stated that in the alternate universe the possible values of ℓ are from 0 to n, instead of o to  n - 1, and that all the other rules are still valid.


5. Since, two electrons in the same atom cannot have the same set of four quantum numbers, and the spin number can only be +1/2 or -1/2, the number of possible orbitals is equal to the amount  of possible ℓ numbers.


That implies that you can build the table with the possible number of orbitgals in each level:


    level     possible values of ℓ     possible values of m     number of orbitals

    n = 1        0, 1                                 -1, 0, 1                                      3

    n = 2       0, 1, 2                             -2, - 1, 0, +1, +2                       5

    n = 3       0, 1, 2, 3                         -3, -2, -1, 0, +1, +2, +3             7    

    n = 4        ...                                    ...                                            9

    n = 5       ...                                    ...                                            11

   n = 6        ...                                    ...                                            13

   n = 7        ...                                    ...                                            15




5 0
4 years ago
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