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2 years ago

11

To study the dependant variable, a scientist must A. manipulate the independent variable B. have more than one control group C.

manipulate the dependent variable D. have more than one experimental group

1 answer:

ankoles [38]2 years ago

6 0

Answer:

A. Manipulate the Independent Variable

Explanation:

How I like to remember is (I)ndependent " I change it"

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What <br> material gives the soil its high fertility?

NARA [144]

Answer:

Humus

Explanation:

Its Humus I believe. I remember learning something like this.

8 0

2 years ago

In a particular run of the “Archimedes principle” experiment a particular unknown substance is found to have a “dry mass” of 4.5

iris [78.8K]

Answer:

D = 18000 kg/m3

V = 2.5*10{-7}m3

Explanation:

From the Archimedes principle,

Weight of fluid displaced = W_{air} - W_{water}

W_{air} = 4.5 gm

W_{water} = 4.25 gm

$W = [4.5 - 4.25]*9.81*10^{-3}$

W = 2.4525*10{-3} N

$\frac{density\ of\ object}{density\ of\ fluid} = \frac{weight\ in\ air}{weight\ of\ displaced\ fluid}$

$Density\ of\ object = \frac{D_{water}*Weight\ in\ air}{weight\ of\ displaced\ water}$

$D = \frac{1000*4.5*10^{-3}*9.8}{2.4525*10^{-3}}N$

D = 18000 kg/m3

b) object Volume can be obtained as ,

$V = \frac{m}{D} = \frac{4.5*10^{-3}}{18000}$

V = 2.5*10{-7}m3

7 0

2 years ago

What is the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m?

notsponge [240]

Answer:

a ) 24 m/s

Explanation:

Given,

Frequency ( f ) = 6 Hz

Wavelength ( λ ) = 4 m

To find : Speed ( v ) = ?

Formula : -

v = f x λ

v

= 4 x 6

= 24 m/s

Therefore, the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m

is 24 m/s.

4 0

3 years ago

Two blocks A and B with mA = 2.6 kg and mB = 0.81 kg are connected by a string of negligible mass. They rest on a frictionless h

vladimir1956 [14]

Answer:

Explanation:

Given

Mass of block A $(m_a)$ =2.6 kg

Mass of block B $(m_b)$ =0.81 kg

Force of 6.5 N is applied on Block A

Force on Block A is F, Tension

thus

$F-T=m_a\times a$ -----1

where a=acceleration of the system

For Block B

$T=m_b\times a$ -----2

$F=m_b\times a+m_a\times a$

$F=\left ( m_a+m_b\right )a$

$F=\left ( 2.6+0.81\right )a$

$a=\frac{6.5}{3.41}$

$a=1.96 m/s^2$

$T=0.81\times 1.96=1.54 N$

5 0

3 years ago

The second ionization energy is the energy required to remove the _______ Electron after a __________ one has been removed.

Sindrei [870]

The second ionization energy is the energy required to remove the <u>second </u>electron after a <u>valence</u> one has been removed.

<h3><u>Explanation:</u></h3>

For an element, the first ionization energy is defined as the amount of energy required to remove one electron from the outermost valence shell of a neutral atom. Removing one electron increases the number of protons, making it a 1+ ion.

The nucleus (protons) has more bonding to the electrons with negative charge and thus more energy is required if another electron needs to be removed. This higher energy required to remove second electron from a 1+ ion (after the first one has been removed) is termed as the second ionization energy. Second ionization energy leads to formation of a 2+ ion. Similarly, third ionization energy is higher than second ionization energy.

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3 years ago