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3 years ago

11

To study the dependant variable, a scientist must A. manipulate the independent variable B. have more than one control group C.

manipulate the dependent variable D. have more than one experimental group

1 answer:

ankoles [38]3 years ago

6 0

Answer:

A. Manipulate the Independent Variable

Explanation:

How I like to remember is (I)ndependent " I change it"

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A particle starts from rest and has an acceleration function 5 − 10t m/s2 . (a) What is the velocity function? (b) What is the p

frez [133]

Explanation:

It is given that,

A particle starts from rest and has an acceleration function as :

$a(t)=(5-10t)\ m/s^2$

(a) Since, $a=\dfrac{dv}{dt}$

v = velocity

$dv=a.dt$

$v=\int(a.dt)$

$v=\int(5-10t)(dt)$

$v=5t-\dfrac{10t^2}{2}=5t-5t^2$

(b) $v=\dfrac{dx}{dt}$

x = position

$x=\int v.dt$

$x=\int (5t-5t^2)dt$

$x=\dfrac{5}{2}t^2-\dfrac{5}{3}t^3$

(c) Velocity function is given by :

$v=5t-5t^2$

$5t-5t^2=0$

t = 1 seconds

So, at t = 1 second the velocity of the particle is zero.

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3 years ago

Compounds are formed as a result of ____

katrin [286]

Compounds are formed as a result of elements that are joined and held together by strong forces called chemical bonds.

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3 years ago

jill's car has a maximum acceleration of 8.7 miles per hour per second. how many seconds does it take her to acceleration from 0

amm1812

T = ?
v1 = 0mph
v2 = 60mph
a = 8.7mph/s

$a = \frac{v2 - v1}{t}
 \\ t = \frac{v2-v1}{a}
 \\ t = \frac{60mph - 0mph}{8.7mph/s}
 \\ t = 6.90s$

Therefore, it takes 6.90 seconds for Jill to accelerate from 0 to 60 miles per hour.

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4 years ago

Physics Homework

katrin2010 [14]

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled. Displacement is the difference between the final position and initial position.

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3 years ago

A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too

maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = $90\times 1.989\times 10^{30}\ kg$

$R_{f}$ = 10000+100 m

$R_{sb}$ = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

$\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2$

The acceleration is 2352645198509.9604 m/s²

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3 years ago