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2 years ago

9

explain the fleming left-hand rule with the diagram and what will the direction of the induced current in the figure if the magn

et is going towards the coil.

1 answer:

iVinArrow [24]2 years ago

4 0

Hi sorry

I don’t know

but maybe next time

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A fairground ride consists of a large vertical drum that spins so

expeople1 [14]

Answer:

v = 3.84 m/s

Explanation:

In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:

$Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}$

where,

v = minimum speed = ?

g = acceleration due to gravity = 9.81 m/s²

r = radius = 10 m

μ = coefficient of friction = 0.15

Therefore,

$v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}$

<u>v = 3.84 m/s</u>

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3 years ago

6. Rock Ais thrown horizontally off a cliff with a velocity of 15 m/s. The rock lands 75m from

Harman [31]

Answer:

5 seconds

Explanation:

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3 years ago

A certain wave has a wavelength of 45.0 meters and a frequency of 9.00 Hz. What is the speed of the wave? 405 m/s 5.00 m/s 0.200

kirill115 [55]

Wave speed = (wavelength) x (frequency)

= (45 meters) x (9 per second)

= 405 meters per second .

5 0

3 years ago

Read 2 more answers

Which statement best describes acceleration?

Brut [27]

Answer:

acceleration is the rate in which your speed increase at a constant or steady rate

Explanation:

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3 years ago

A non-ideal 12.2 V battery is connected across a resistor R. The internal resistance of the battery is 1.9Ohm. Calculate the pot

Brums [2.3K]

Answer:

R=100 Ohm, V=11.97 volts and I=0.12 amperes

R=10 Ohm, V=10.25 volts and I=1.20 amperes

R=2 Ohm, V=6.26 volts

Explanation:

The potential difference (voltage) of a battery with internal resistance is:

$V=\xi-Ir$ (1)

with $\xi$ the electromotive force (the voltage the batteries say to has) , I the current and r the internal resistance. By Ohm's law the current that passes through the resistor is:

$I=\frac{V}{R}$ (2)

using (2) on (1):

$V=\xi-\frac{V*r}{R}$

solving for V:

$V+\frac{V*r}{R}=\xi$

$V=\frac{\xi}{1+\frac{r}{R}}$ (3)

R=100 Ohm

$V=\frac{12.2}{1+\frac{1.9}{100}}=11.97 V$

R=10 Ohm

$V=\frac{12.2}{1+\frac{1.9}{10}}=10.25 V$

R=2 Ohm

$V=\frac{12.2}{1+\frac{1.9}{2}}=6.26 V$

Because we have now the values of I on the circuit (is the same through all the components because is a series circuit)

We use back substitution on (1) to find the current:

R=100 Ohm

$I=\frac{V}{R}=\frac{11.97}{100}=0.12 A$

R=10 Ohm

$I=\frac{V}{R}=\frac{11.97}{10}=1.20 A$

7 0

3 years ago