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wolverine [178]
3 years ago
12

A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu

gh an angle of 80 radians. Assuming the wheel started from rest, how long had it been in motion at the start of the 4.0-s interval
Physics
1 answer:
Nady [450]3 years ago
4 0

Answer:

The  time interval is  t =  3 \ s

Explanation:

From the question we are told that

    The angular acceleration is  \alpha  =  4.0 \ rad/s^2

     The  time taken is  t  =  4.0 \ s

      The angular displacement is  \theta  = 80 \ radians

     

The angular displacement can be represented by the second equation of motion as shown below

          \theta =  w_i t  +  \frac{1}{2} \alpha t^2

where  w_i is the initial velocity at the start of the 4 second interval

So substituting values

        80 =  w_i *  4 + 0.5 *  4.0 *  (4^2)

=>    w_i  =  12 \ rad/s

Now considering this motion starting from the start point (that is rest ) we have

       w__{4.0 }} =  w__{0}} +  \alpha  * t

Where  w__{0}} is the angular velocity at rest which is zero  and  w__{4}} is the angular velocity after 4.0 second which is calculated as 12 rad/s s

        12 =  0  + 4 t

=>       t =  3 \ s

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If it takes you 20 joules of work to move a couch 10 meters in 10 seconds, what is the power?
Debora [2.8K]

Answer:

Power = 2 j/s

Explanation:

Power = Work / Time

= 20/10

= 2 j/s

4 0
2 years ago
During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±
Alla [95]

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         ΔP_{y} = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / P_{y}

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

7 0
3 years ago
Please do number 25! Explain how you got your answer with detail to get Brainliest! Thank you!
Ad libitum [116K]
John weighs 200 pounds.
In order to lift himself up to a higher place, he has to exert force of 200 lbs.

The stairs to the balcony are 20-ft high.
In order to lift himself to the balcony, John has to do
(20 ft) x (200 pounds)  =  4,000 foot-pounds of work.

If he does it in 6.2 seconds, his RATE of doing work is
(4,000 foot-pounds) / (6.2 seconds)  =  645.2 foot-pounds per second.

The rate of doing work is called "power".

(If we were working in the metric system (with SI units),
the force would be in "newtons", the distance would be in "meters",
1 newton-meter of work would be 1 "joule" of work, and
1 joule of work per second would be 1 "watt".
Too bad we're not working with metric units.)

So back to our problem.

John has to do 4,000 foot-pounds of work to lift himself up to the balcony,
and he's able to do it at the rate of 645.2 foot-pounds per second.

Well, 550 foot-pounds per second is called 1 "horsepower".

So as John runs up the steps to the balcony, he's doing the work
at the rate of

           (645.2 foot-pounds/second) / (550 ft-lbs/sec per HP)

=  1.173 Horsepower.  GO JOHN !

(I'll betcha he needs a shower after he does THAT 3 times.)
_______________________________________________

Oh my gosh !  Look at #26 !  There are the metric units I was talking about.

Do you need #26 ?

I'll give you the answers, but I won't go through the explanation,
because I'm doing all this for only 5 points.

a).  5
b).  750 Joules
c).  800 Joules
d).  93.75%

You're welcome.

And #27 is 0.667 m/s .
7 0
3 years ago
A student who was training for a cross country race jogged for 2. 0 hours and covered a distance of 14. 0 kilometers. What was t
FinnZ [79.3K]

The average speed is 116.66m/s.

Given - The path traced is 14km , time for jogging is 2 hrs=120min

To find the average speed-

  1. Speed refers to the ease of the movement and degree of mobility as a result of force application.
  2. Due to this there is involvement of velocity.
  3. Journey of average speed is the cumulative of distances and time.
  4. Kinetic theory refers to the Boltzmann constant connecting to the standards of distance traversed.

calculations-

Speed= \frac{Distance}{Time}

Speed= 14 000 / 120

= 116.66m/s

To learn more about average speed -

<u>brainly.com/question/27753148</u>

#SPJ4

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1 year ago
What causes seasons to occur?
LUCKY_DIMON [66]
It’s C I hope it helps you
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3 years ago
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