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wolverine [178]
3 years ago
12

A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu

gh an angle of 80 radians. Assuming the wheel started from rest, how long had it been in motion at the start of the 4.0-s interval
Physics
1 answer:
Nady [450]3 years ago
4 0

Answer:

The  time interval is  t =  3 \ s

Explanation:

From the question we are told that

    The angular acceleration is  \alpha  =  4.0 \ rad/s^2

     The  time taken is  t  =  4.0 \ s

      The angular displacement is  \theta  = 80 \ radians

     

The angular displacement can be represented by the second equation of motion as shown below

          \theta =  w_i t  +  \frac{1}{2} \alpha t^2

where  w_i is the initial velocity at the start of the 4 second interval

So substituting values

        80 =  w_i *  4 + 0.5 *  4.0 *  (4^2)

=>    w_i  =  12 \ rad/s

Now considering this motion starting from the start point (that is rest ) we have

       w__{4.0 }} =  w__{0}} +  \alpha  * t

Where  w__{0}} is the angular velocity at rest which is zero  and  w__{4}} is the angular velocity after 4.0 second which is calculated as 12 rad/s s

        12 =  0  + 4 t

=>       t =  3 \ s

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Marizza181 [45]

Answer:

The answer to your question is va = 8 cm/s, vb = 12.5 cm/s, a = 9 cm/s²

Explanation:

Data

Ta = 0.125 s

Tb = 0.08 s

Δtab = 0.5 s

distance = 1 cm

Process

1.- Calculate va

va = 1/0.125 = 8 cm/s

vb = 1/0.08 = 12.5 cm/s

2.- Calculate Δv

Δv = 12.5 - 8

Δv = 4.5 cm/s

3.- Calculate acceleration

a = Δv / Δt

a = 4.5/0.5

a = 9 cm/s²

4 0
3 years ago
A race car moving along a circular track has a centripetal acceleration of 15.4 m/s? If the car has
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Answer:

r = 58.44 [m]

Explanation:

To solve this problem we must use the following equation that relates the centripetal acceleration with the tangential velocity and the radius of rotation.

a = v²/r

where:

a = centripetal acceleration = 15.4 [m/s²]

v = tangential speed = 30 [m/s]

r = radius or distance [m]

r = v²/a

r = 30²/15.4

r = 58.44 [m]

3 0
3 years ago
Help please help!! Pleaseee
sladkih [1.3K]

Answer:

The coastal regions are affected by abrasion due to large volumes of water and increased winds. This can become more severe especially with storms that hit coastal regions.

Explanation:

Abrasion is physical weathering caused by water, wind and gravity.  Hope it worked, I love geography! Can you mark mine as the brainliest please! Also can you give me a thanks and a 5 star vote!

5 0
3 years ago
A free positive charge released in an electric field will:
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Answer:

accelerate in the direction in which the electric field is pointing.

Explanation:

The positive charge feels a force in the same direction as the electric field

F=Eq  

F and E are vectors, q is a scalar

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that force will produce an acceleration in the same direction, that acceleration will cause the particle to move in the same direction, ie the direction of the electric field.

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A jet aircraft is traveling at 262 m/s in hor-
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Solution :

Speed of the air craft, $S_a$ = 262 m/s

Fuel burns at the rate of, $S_b$ = 3.92 kg/s

Rate at which the engine takes in air, $S_{air}$ = 85.9 kg/s

Speed of the exhaust gas that are ejected relative to the aircraft, $S_{exh}$ =921 m/s

Therefore, the upward thrust of the jet engine is given by

$F=S_{air}(S_{exh}-S_a)+(S_b \times S_{exh})$

F = 85.9(921 - 262) + (3.92 x 921)

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Therefore thrust of the jet engine is $4.8 \times 10^6 \ N$.

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