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Temka [501]
3 years ago
12

Which object absorbs the most visible light

Physics
1 answer:
Papessa [141]3 years ago
4 0
The objects that look black are all tied for first place.
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a fan acquires a speed of 180 rpm in 4s, starting from rest. calculate the speed of the fan at the end of the 5th second startin
KengaRu [80]

Answer:

225 rpm

Explanation:

The angular acceleration of the fan is given by:

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

where

\omega_f is the final angular speed

\omega_i is the initial angular speed

\Delta t is the time interval

For the fan in this problem,

\omega_i = 0\\\omega_f = 180 rpm\\\Delta t=4 s

Substituting,

\alpha = \frac{180-0}{4}=45 rpm/s

Now we can find the angular speed of the fan at the end of the 5th second, so after t = 5 s. It is given by:

\omega' = \omega_i + \alpha t

where

\omega_i = 0\\\alpha = 45 rpm/s\\t = 5 s

Substituting,

\omega' = 0 + (45)(5)=225 rpm

7 0
3 years ago
A car traveling at 60 km/h will skid 30 m when its brakes are locked. if the same care is traveling at 180 km/h, what will be th
Flauer [41]
The first car travels at 60km/h and skid at 30m away from the starting point while another car is also traveling at 180km/h. Now, we need to solve for the skidding distance.
We assigned variables such as:
V1=60km/h
V2=180km/h
Skid1=30m
Skid2=?
We solve this by ratio and proportion method such as shown below:
V1/V2=skid1/skid2
60/180=30/skid2
skid2=(30*180)/60
skid2=90meters

Th answer is 90 meters.
3 0
3 years ago
Read 2 more answers
The odometer of a car changes from 1048 km to 1096 km in 40
Makovka662 [10]

Answer:

20m/s

Explanation:

it covers 20 metres in a second

3 0
2 years ago
A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
A gardener uses a water hose to fill a 30.0 L bucket. The gardener notes that it takes 1.00 min to fill the bucket. A nozzle wit
GalinKa [24]

Answer:

The distance can the water be projected is 4.51 m

Explanation:

The speed of the water in the hose is equal to:

v1 = R/A1

If we solve the continuity for v2:

v2 = R/A2 (eq. 1)

The equation for the vertical position is:

yf = yi + vy*t - (1/2)gt²

yi = 0

vy = 0

Clearing t:

t=\sqrt{\frac{-2y_{f} }{g} } (eq. 2)

The equation for position is:

xf = xi + vxt = 0 + v2t = v2t (eq. 3)

Replacing equation 1 and 2 in equation 3:

x_{f} =\frac{R}{A_{2}  } \sqrt{\frac{-2y_{f} }{g} } =\frac{30}{0.5} \sqrt{\frac{(-2)*(-1)}{9.8} }*\frac{1000}{60}  =451.75cm=4.51m

6 0
3 years ago
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