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jonny [76]
3 years ago
13

On a warm, balmy summer day you decide to relax by watching the latest building renovation in your neighborhood. You notice that

a very heavy wrecking ball is attached to a much lighter chain and is dangling from a crane and swinging back and forth. As long as it does not swing too high the time it takes the wrecking ball to complete one full oscillation will be independent of A) the weight of the ball, but not the amplitude of the motion.B) both the amplitude of the motion and the weight of the ball.C) both the length of the chain supporting the ball and the amplitude of the motion.D) the amplitude of the motion, but not the weight of the ball.
Physics
1 answer:
liq [111]3 years ago
8 0

Answer:

B) both the amplitude of the motion and the weight of the ball

Explanation:

Time period of a pendulum is given by

T=2\pi \sqrt{\dfrac{L}{g}}

where,

L = Length of pendulum

g = Acceleration due to gravity

The system here is similar to a simple pendulum

It can be seen that the time period depends on L and g.

Amplitude and weight are the factors that do not determine the time period.

Hence, the answer is B) both the amplitude of the motion and the weight of the ball

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How long does it take the moon to go through an entire set of phases?
Vanyuwa [196]

Answer:

The Moon takes 27.3 days to orbit Earth, but the lunar phase cycle (from new Moon to new Moon) is 29.5 days

7 0
2 years ago
2 kg steel ball is dropped straight down ont a hard horixontal florr and bounces straight up . the balls speed just before and j
Rainbow [258]

Answer:

40 \frac{kg*m}{s}

Explanation:

Impulse-momentum theorem states that impulse is equal to the change of momentum:

\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i} (1)

with pf the final momentum and pi the initial momentum. Knowing that momentum is mass (m) times velocity (1) is:

\overrightarrow{J}=m \overrightarrow{v}_{f}- m \overrightarrow{v}_{i}

It's important to note that we're dealing with vector quantities so direction matters. If we choose towards the floor positive direction then the initial velocity is positive and the final velocity is negative, so:

\overrightarrow{J}=-(2kg)(10\frac{m}{s}) - (2.0kg)(10\frac{m}{s})

\overrightarrow{J}=-40 \frac{kg*m}{s}

So, the impulse delivered to the floor is 40 \frac{kg*m}{s}

5 0
2 years ago
Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of lig
PSYCHO15rus [73]
Give me some answer choices and i will be happy to help
4 0
3 years ago
Which of the following is an example of an electric force?
inysia [295]

The example of electric force in the given question is a Plastic wrap sticks to glass bowl containing leftovers. Option A is the right answer.

ELECTRIC FORCE

According to Coulomb's law, the electric force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

The electric force can be:

  • Force of attraction
  • Force of repulsion

The electric force can be exhibited in both static and current electricity. Example of static electricity are;

  • a glass rod rub with fur
  • an ebonite rod rub with silk.
  • e.t.c

The example of electric force in the given question is a Plastic wrap sticks to glass bowl containing leftovers.

The plastic wrap is able to stick to glass bowl container because of the force of attraction between the plastic wrap and the glass bowl container.

Therefore, the correct answer is the option A

Learn more about Electric Force here: brainly.com/question/4053816

8 0
2 years ago
A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds.
Vlad1618 [11]
Since car is accelerating uniformly that means we it is accelerating at constant rate if you can say that way. To find its acceleration all we have to do is find difference between v1=13 m/s and v2 = 25m/s   and divide it by interval that car is taking to accelerate.

a = (v2-v1)/t = 2,4m/s^2

since car is accelerating at constat rate and truck covers same distance as car needs to accelerate from 13 to 25m that means that we can say that in that period truck travelled at cars average speed.

Vtruck = (v1 + v2)/2 = 19m/s
4 0
3 years ago
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