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Alexxx [7]
3 years ago
9

A car skids to a stop. What happens to its kinetic energy?

Physics
1 answer:
Orlov [11]3 years ago
4 0

Answer:

a) it turns into thermal energy

Explanation:

Due to the law of energy conservation, an object cannot just "lose" its kinetic energy, it must become another type of energy.

This eliminates option b. because energy of any type cannot disappear.

About option c, we have that the kinetic energy becomes potential energy, but the potential energy of an object is due to its height above the ground, so we cannot have potential energy if the tires are on the floor, we discard option c.

Also, kinetic energy is the energy an object has due to its motion, this means that if the object is not moving, it cannot have kinetic energy.

This eliminates option d.

The correct option is a) it turns into thermal energy.

The option meets the characteristic that the kinetic energy does not disappear, it is transformed into another type of energy. In this case it is thermal energy or heat, generated by friction between the tires and the floor.

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A driver slammed on her brakes and came to a stop with constant acceleration. Measurements on her tires and skid marks on the pa
IRISSAK [1]

Answer:

u = 29.22 m/s

Explanation:

distance (s) = 58.52 m

coefficient of kinetic friction (k) = 0.75

final velocity (v) = 0 m/s

acceleration due to gravity (g) = 9.8 m/s^{2}

How fast was she driving (u)

we can get how fast she was driving by using the formula below

s = ut - \frac{1}{2}.at^{2}  ...equation 1

where

  • s = distance
  • u = her initial velocity
  • a = acceleration = \frac{f}{m} = \frac{kmg}{m} = kg
  • k = coefficient of kinetic friction
  • g = acceleration due to gravity
  • t = time

        from v = u - at  (recall that v = 0)

        0 = u - at, therefore t = u/a = u/kg

now substituting the required values above into equation 1 we have

s = \frac{u^{2}}{kg} - \frac{u^{2}}{2kg}

s = \frac{u^{2}}{2kg}

u = \sqrt{2kgs}

u = \sqrt{2 x 0.75 x 9.8 x 58.52}

u = 29.22 m/s

8 0
3 years ago
I REALLY NEED HELP PLEASE!!! CAN SOMEONE ANSWER THIS? At 0 ºC, some amount of energy is required to change 1 kg of water from a
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Answer:

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Answer:

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The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

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From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

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