All categories

4 years ago

List the components in the proportion relationship used to find missing value in scale drawing?

Mathematics

1 answer:

Phoenix [80]4 years ago

3 0

<h2>Explanation:</h2><h2></h2>

When we have relationships between two variables and their ratios are equivalent, we call this as proportional relationship. A scale drawing is a model that has been reduced or enlarged from its original size. Suppose you have a horse that measures 1,5m high by 2m long and want to draw a reduced model by a scale factor of 1:10, then your drawing will measure:

$Height=1.5(1/10)=0.15m \\ \\ Length=2(1/10)=0.2m$

So the components are:

Measurements of the original object
Measurements of the drawing
Scale factor

You might be interested in

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

4 years ago

A sequence can be generated by using an=1/4an−1, where n is a whole number greater than or equal to 1.

harina [27]

Answer: its 40

Step-by-step explanation:

4 0

3 years ago

How to find slope? I'm confused on using y=mx+b

Mumz [18]

Slope is mx is that makes sense

4 0

4 years ago

Read 2 more answers

Simplify (2 {sqrt 5}+ 3 {sqrt 7})^2. Show your work. Justify each step.

White raven [17]

(2√5 + 3(√7))^2
(2√5 + 3(√7))(2√5 + 3(√7))
4*5 + 6√35 + 6√35 + 9*7
20 + 12√35 + 63
20 + 63 + 12√35
83 + 12√35

4 0

4 years ago

Batman (mass=100 kg) jumps straight down from a bridge in to a boat (mass = 580 kg) in which a criminal is fleeing. The velocity

Crank

Answer:

$v_b=11.94\ m/s$

Step-by-step explanation:

<u>Linear Momentum </u>

The momentum of a system of masses m1,m2,m3... with speeds v1,v2,v3,... is given by

$M=m_1v_1+m_2v_2+m_3v_3+...$

When some interactions take place into the system of masses with no external forces interferring, the total momentum is not changed, which means that if the new speeds are v1', v2', v3'... then:

$m_1v_1+m_2v_2+m_3v_3+...=m_1v_1'+m_2v_2'+m_3v_3'+...$

The problem relates the story of Batman (m1=100kg) who is initially assumed at rest and lands on a boat with mass m2=580 kg initially moving at 14 m/s to the positive reference. When the collision takes place, both masses join and a common speed $v_b$ is achieved by the common mass. Applying the conservation of momentum, we have