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julsineya [31]
2 years ago
12

At the instant a traffic light turns green, a car starts from rest with a given constant acceleration of 0.5 m/s squared. Just a

s the light turns green, a bus, traveling with a given constant speed 16.0 m/s, passes the car. The car speeds up and passes the bus sometime later. How far down the road has the car traveled when the car passes the bus?
Physics
1 answer:
lubasha [3.4K]2 years ago
5 0

Answer:

d= 1024 m

Explanation:

Kinematics of the car

The car moves with uniformly accelerated movement we apply the following formula:

d= v₀t+ (1/2)*a*t² Formula (1)

Where:  

d:displacement in meters (m)  

t : time in seconds (s)

v₀: initial speed in m/s  

a: acceleration in m/s²

Data

v₀₁= 0   :initial speed of the car

a₁ =0.5 m/s² : acceleration of the car

Kinematics equation of the car

We replace data in the formula (1) :

d= 0+ (1/2)*0.5*t²

d= (0.25)*t²  Equation (1)

Kinematics of the bus

The car moves with uniformly movement ( constant speed) we apply the following formulas:

d= v*t   Formula (2)

Where:  

d:displacement in meters (m)  

t : time in seconds (s)

Data

v =  16 m/s

Kinematics equation of the bus

We replace data in the formula (2) :

d= 16*t   Equation (2)

<em>Problem development</em>

when the car passes the bus the elapsed time (t) and the distance (d) is equal for both.

Equation (1) = Equation (2)=d

(0.25)*t² =16*t  We divide both sides of the equation by t

(0.25)*t = 16

t= 16/(0.25)

t= 64 s

We replace t in the equation  (2)

d= 16*t

d= 16*(64)

d= 1024 m

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Answer:

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Explanation:

Pressure due to car = pressure due to applied force  

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12000*pi*(5^2) = F2 ( pi)*(18^2)

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Pascal's principle

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F1/A1 = F2/A2 (F=force and A=area)

A1 =Pi*(0.05)²

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7 0
3 years ago
2 forces are acting on a body. I forgot the body doesn't it's position or shape, the forces.......a)must be of equal magnitude b
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C

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3 years ago
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Andreyy89

Answer:

Energy, E = 178.36 J

Explanation:

It is given that,

Mass 1, m_1=4\ kg

Mass 2, m_2=4\ kg

Mass 3, m_3=6\ kg

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What is the force exerted on a charge of 2.5 µC moving perpendicular through a magnetic field of 3.0 × 102 T with a velocity of
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Given:

B = 3 \times 10^{2} T

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To find:

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Formula used:

Force on the moving charge is given by,

F = q V B sin α

Where F = force exerted on moving charge

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Solution:

F = q V B sin α

Where F = force exerted on moving charge

V = velocity of charge

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α = angle between direction of V and B

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Answer:

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Explanation:

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Therefore, the change in temperature  is 10.21°C

7 0
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