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4 years ago

In the metric system, the appropriate unit for weight is the _____. gram newton newton/cm2 gram/cm3

Physics

1 answer:

Archy [21]4 years ago

4 0

Answer:

Newton

Explanation:

The earth attracts every body towards its centre. The force with which the earth attracts any body towards its centre, is called its weight.

It is a vector quantity.

It always acts towards the centre of earth.

The SI unit of Newton.

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I need help with this problem :(

Reil [10]

Answer:

it tells you that the speed increases until about 20 seconds then keeps a steady pace for 20 seconds then the speed drops and stops at 55 seconds in the process.

7 0

3 years ago

Radiation from the Sun reaching Earth (just outside the atmosphere) has an intensity of 1.4 kW/m2. (a) Assuming that Earth (and

baherus [9]

To solve the problem we will require the concept of Force as a definition of pressure and Area, and the concept of light pressure itself determined by the relationship between intensity and the speed at which light travels. We will match the terms and find the desired force value,

$F = PA$

Here,

P = Pressure

A = Area

Pressure due to the light of the sun will be

$P= \frac{I}{c}$

Here,

I = Intensity

c = Speed velocity

Equation both therms we have that

$F = \frac{IA}{c}$

We have a circular area then

$F = \frac{I(\pi r^2)}{c}$

Replacing with our values (Adding the radius of the Earth)

$F = \frac{(1.4*10^3W/m^2)(\pi (6.32*10^6m)^2)}{3.0*10^8m/s}$

$F = 6.0*10^8N$

Therefore the Force on Earth due to radiation pressure is $6*10^8N$

4 0

3 years ago

The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a

likoan [24]

Answer:

14869817.395 m

Explanation:

$\theta$ =22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

$22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians$

From Rayleigh Criterion

$\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m$

Diameter of the effective primary objective is 14869817.395 m

It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.

7 0

3 years ago

A slingshot fires a pebble from the top of a building at a speed of 14.7 m/s. The building is 36.0 m tall. Ignoring air resistan

monitta

Answer:

The final speed is 30.37 m/s for the three directions.

Explanation:

Given the initial speed, v₀ = 14.7 m/s and the height of the building as 36.0 m (neglecting air resistance and height of slingshot), we apply the principle of Conversation of Mechanical Energy:

E = Kinetic Energy (k.E) + Potential Energy (P.E)

K.E = 0.5mv²

P.E = mgh

∴ 0.5mv₀² + mgh₀ = 0.5mv₁² + mgh₁

Since the final height (h₁) is zero and m is a common term, then we can re-write the above equation as:

0.5v₀² + gh₀ = 0.5v₁² + 0

0.5v₁² - 0.5v₀² = gh₀

0.5(v₁² - v₀²) = gh₀

v₁² = v₀² + 2gh₀

Fitting in the given terms, we can calculate the final speed

v₁² = (14.7)² + (2)(9.81)(36.0)

= 216.09 + 706.32 = 922.41

v₁ = √922.41 = 30.37 m/s.

The speed at which the pebble hits the ground remains the same because kinetic energy depends on the speed of the object and not the direction to which the object is thrown.

7 0

4 years ago

Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10

Nezavi [6.7K]

Answer:

t = 23.9nS

Explanation:

given :

Area A= 10 cm by 2 cm => 2 x 10^-2m x 10 x 10^-2m

distance d= 1mm=> 0.001

resistor R= 975 ohm

Capacitance can be calculated through the following formula,

C = (ε0 x A )/d

C = (8.85 x 10^-12 x (2 x 10^-2 x 10 x 10^-2))/0.001

C = 17.7 x 10^-12 (pico 'p' = 10^-12)

C = 17.7pF

the voltage between two plates is related to time, There we use the following formula of the final voltage

Vc = Vx (1-e^-(t/CR))

75 = 100 x (1-e^-(t/CR))

75/100 = (1-e^-(t/CR))

.75 = (1-e^-(t/CR))

.75 -1 = -e^-(t/CR)

-0.25 = -e^-(t/CR) --->(cancelling out the negative sign)

e^-(t/CR) = 0.25

in order to remove the exponent, take logs on both sides

-t/CR = ln (0.25)

t/CR = -ln(0.25)

t = -CR x ln (0.25)

t = -(17.7 x 10^-12 x 975) x (-1.38629)

t = 23.9 x $10^{-9$

t = 23.9ns

Thus, it took 23.9ns for the potential difference between the deflection plates to reach 75 volts

6 0

3 years ago

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