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Yakvenalex [24]
3 years ago
11

Which of the following represents an image that is located behind a mirror?

Physics
2 answers:
9966 [12]3 years ago
3 0

Answer:

i think its -di........

Marina CMI [18]3 years ago
3 0

Explanation:

There are some conventions while solving the problems based on mirrors. All parameters are taken like x-y coordinate system.

All the measurements are done from the optical centre of the mirror.

d_i is the image distance

d_o is the object distance

-d_i is the image distance which is formed behind the mirror.

-d_o is the object distance when an object is placed behind the mirror.

So, -d_i shows the image that is located behind the mirror. Hence, this is the required solution.

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True or false Variables are those factors that can be changed in an experiment
tekilochka [14]
True

Variables is changing. It is any factor, trait or condition that can exist in differing amounts or types. An experiment has three types: Independent, Dependent and Controlled.
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3 years ago
Recall some things you already know about projectile motion. Does a force in the vertical direction affect the horizontal compon
azamat

Answer:

vertical force cannot change the velocity on the x-axis.   t =x/v₀ₓ

Explanation:

The force is a vector magnitude, so the forces on the x-axis affect the acceleration on this axis. Consequently a vertical force cannot change the velocity on the x-axis.

     F_{y} = m g

    Fₓ = 0

The horizontal velocity in projectile motion is constant, if we neglect the air resistance, so it can be used to find the time of a horizontal displacement

       x = v₀ₓ t

       t =x/v₀ₓ

The only magnitude that is the same for both movements is the time that is a scalar

7 0
4 years ago
Which of the following is known as the following cycle because it's reservoir is a rock.
inessss [21]

Letra a obrigadoaijahahavqvqgqgqg

3 0
3 years ago
An example for curvilinear motion.
Shkiper50 [21]

Ball thrown into the air at an angle.

5 0
3 years ago
Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point. F⃗ 1F→1F_1_vec has a magnitude of 9.20 NN and is directed at an a
marishachu [46]

Answer:

-9.46 N

Explanation:

In order to get the value of the x component of the resultant force, we need to get the value of the x component of each force.

This value will be the projection of the force vector, on the x-axis.

For F₁, as it is directed at an angle of 55.0º above the negative x axis, we can find F₁ₓ just applying the definition of cosine of an angle, as follows:

cos θ = \frac{x}{r}

In this case, x = F₁ₓ, and r = F₁

θ, measured from the positive x axis counterclockwise, is as follows:

θ= 180º-55º = 125º

⇒ F₁ₓ = F₁* cosθ = 9.2 N * cos 125º = -5.28 N

We can repeat the process for F₂, as follows:

For F₂, as it is directed at an angle of 53.3º below the negative x axis, we can find F₂ₓ just applying the definition of cosine of an angle, as follows:

cos θ = \frac{x}{r}

In this case, x = F₂ₓ, and r = F₂

θ, measured from the positive x axis counterclockwise, is as follows:

θ= 180º + 53.3º = 233.3º

⇒ F₂ₓ = F₂* cosθ = 7.00 N * cos 233.3º = -4.18 N

The total component of both forces along the x axis, can be found just adding both components, as follows:

Fₓ = F₁ₓ + F₂ₓ = -5.28 N + -4.18 N = -9.46 N

5 0
3 years ago
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