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3 years ago

Which of the following represents an image that is located behind a mirror?

Physics

2 answers:

9966 [12]3 years ago

3 0

Answer:

i think its -di........

Marina CMI [18]3 years ago

3 0

Explanation:

There are some conventions while solving the problems based on mirrors. All parameters are taken like x-y coordinate system.

All the measurements are done from the optical centre of the mirror.

$d_i$ is the image distance

$d_o$ is the object distance

$-d_i$ is the image distance which is formed behind the mirror.

$-d_o$ is the object distance when an object is placed behind the mirror.

So, $-d_i$ shows the image that is located behind the mirror. Hence, this is the required solution.

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The school bag of four students A,B,C,D measures 9kg, 2800gm, 2kg and 8000gm respectively. Whose bag is the lightest

inna [77]

Answer:

Student C

Explanation:

order from heaviest to lightest is...

9 kg (A) , 8000g (8 kg) (D) , 2800g (2.8kg) (B), 2 kg (C)

5 0

3 years ago

Ill mark as brainliest.

rewona [7]

Answer: 75V

Explanation:

Given that,

total resistance (Rtotal) = 150Ω

Current (I) = 0.5A

Change in electric potential (V) = ?

Recall that potential difference is the product of amount of current and the amount of resistance in the circuit. And its unit is volts.

So, apply the formula V = I x Rtotal

V = 0.5A x 150Ω

V = 75V

Thus, the change in electric potential across the circuit is 75 Volts

8 0

3 years ago

. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to

d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

$B = 5 \times 10^{-6} T$

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

$B = \frac{\mu_o i}{2\pi r}$

here we we will find the magnetic field due to wire which is along x axis is given as

$i = 30 A$

r = 2 m

now we have

$B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}$

$B_1 = 3\times 10^{-6} T$ into the plane

Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

$i = 40 A$

r = 2 m

now we have

$B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}$

$B_2 = 4\times 10^{-6} T$ along + x direction

Since the two magnetic field is perpendicular to each other

So here net magnetic field is given as

$B = \sqrt{B_1^2 + B_2^2}$

$B = 5 \times 10^{-6} T$

5 0

3 years ago

A pebble is thrown into a calm lake, ripples are formed from the center and move outward. The water particles in the lake travel

Misha Larkins [42]

Answer: The option (C) is correct. The energy travels horizontally.

Explanation: When the pebble is thrown into a calm lake, there will be disturbance in the lake. The ripples are formed from the center and move outward because the energy is carried out from particle to particle.

The distribution of the energy among the particles starts from center and it will carry out outward. This disturbance will occur horizontally.

Therefore, the energy travels horizontally.

7 0

3 years ago

Which of the following best describes the type of bond formed when sodium reacts with chlorine?

SVEN [57.7K]

Answer: ionic bond

Explanation: This type of chemical bond is called an ionic bond because the bond formed between two ions of opposite charge.

6 0

3 years ago