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Inga [223]
4 years ago
13

Which operation can be used with the augmented matrix below?

Mathematics
1 answer:
ycow [4]4 years ago
5 0

Answer:

Multiply row 2 by-1 and add it to row 3.

Step-by-step explanation:

The given augmented matrix is \left[\begin{array}{ccc}3&-21&15\\15&8&15\\-2&-1&3\end{array}\right]

The permissible row operations are:

1. Switching rows

2. Multiplying a row by a nonzero constant.

3. Adding/Subtracting two rows

 Therefore the correct option is: Multiply row 2 by-1 and add it to row 3.

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141.75 rounded to the nearest hundredth
muminat

Answer:

141.75

Step-by-step explanation:

Since it is already rounded to the nearest hundredth, you don't need to do anything.

6 0
3 years ago
Please answer this question
elena-14-01-66 [18.8K]
The area of the base (six triangles with a base 15m and a height 7.5√3m):

A_B=6\cdot\dfrac{1}{2}\cdot15\cdot7.5\sqrt3\approx585\ m^2

The area of side walls (six triangles with a base 15m and a height 12m)

A_W=6\cdot\dfrac{1}{2}\cdot15\cdot12=540\ m^2

The surface area:

A_B+A_W=585+540=1,125\ m^2



8 0
3 years ago
PLEASE HELP! 40 POINTS
Misha Larkins [42]

Answer:

C

Step-by-step explanation:

the area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

here b = z and h = w , then

A = \frac{1}{2} zw

3 0
2 years ago
In the quadratic formula , what is the expression for the discriminant?
uysha [10]

Answer:

gldfnlmnjmklzj'mgihjz'mhmcvkbmzcvbhjn'ifhd

fjjghnmj'

smhjopfmhjgfnmhjj

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23

Step-by-step explanation:;gjnmtrsJL:gkjnolfj

sopkajr

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6 0
3 years ago
Find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW
valkas [14]

Answer:

see explanation

Step-by-step explanation:

Using the Sine rule in all 3 questions

(1)

\frac{a}{sinA} = \frac{b}{sinB} , substitute values , firstly calculating ∠ B

[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]

\frac{a}{sin78} = \frac{18}{sin53} ( cross- multiply )

a sin53° = 18 sin78° ( divide both sides by sin53° )

a = \frac{18sin78}{sin53} ≈ 22.0 ( to the nearest tenth )

(3)

\frac{c}{sinC} = \frac{a}{sinA} , substitute values

\frac{35}{sinC} = \frac{45}{sin134} ( cross- multiply )

45 sinC = 35 sin134° ( divide both sides by 35 )

sinC = \frac{35sin134}{45} , then

∠ C = sin^{-1} ( \frac{35sin134}{45} ) ≈ 34.0° ( to the nearest tenth )

(5)

Calculate the measure of ∠ B

∠ B = 180° - (38 + 92)° = 180° - 130° = 50°

\frac{a}{sinA} = \frac{b}{sinB} , substitute values

\frac{BC}{sin38} = \frac{10}{sin50} ( cross- multiply )

BC sin50° = 10 sin38° ( divide both sides by sin50° )

BC = \frac{10sin38}{sin50} ≈ 8.0 ( to the nearest tenth )

3 0
3 years ago
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