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Inga [223]
3 years ago
13

Which operation can be used with the augmented matrix below?

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

Multiply row 2 by-1 and add it to row 3.

Step-by-step explanation:

The given augmented matrix is \left[\begin{array}{ccc}3&-21&15\\15&8&15\\-2&-1&3\end{array}\right]

The permissible row operations are:

1. Switching rows

2. Multiplying a row by a nonzero constant.

3. Adding/Subtracting two rows

 Therefore the correct option is: Multiply row 2 by-1 and add it to row 3.

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Step-by-step explanation:

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What are the next three terms in the sequence 11,18,25,32
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Read 2 more answers
At a baseball game, 3 drinks and 4 hotdogs cost $15.00. At the same game, 3 drinks and 1 hotdog cost $10.50. Find the cost for a
Serhud [2]

Answer:

$3

Step-by-step explanation:

Given data

Let the cost of drinks be x

and the cost of hotdogs be y

so

3x+4y=15-------1

also

3x+y= 10.5------2

solve 1 and 2

 3x+4y=15

-3x+y= 10.5

     3y= 4.5

divide both sides by 3

y= 4.5/3

y= $1.5

Put y= 1.5 in 1

3x+4(1.5)=15

3x+6= 15

3x=15-6

3x= 9

x= 9/3

x= $3

Hence the cost of a drink is $3

8 0
3 years ago
A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan
seropon [69]

Answer:

32 unit^{3}

Step-by-step explanation:

Given:

  • The slant length 10 units
  • A right square pyramid with base edges of length 8\sqrt{2}

Now we use  Pythagoras to get the slant height in the middle of each triangle:

\sqrt{10^{2 - (4\sqrt{2} ^{2} }) } = \sqrt{100 - 32} = \sqrt{68}  units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

\sqrt{68-(4\sqrt{2} ^{2} )} = \sqrt{68 - 32} = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

  • The height 3 units
  • A right square pyramid with base edges of length 4\sqrt{2}

So the volume of it is:

V  = 1/3 *3* 4\sqrt{2}

= 32 unit^{3}

5 0
3 years ago
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