We're going to remedy it with the parallelogram law.

= one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin

/3 = sin(eighty)/three.304 = 63.4 stages
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
Let us use the formula for Newton's Second Law of Motion:
Net force = Mass*Acceleration
Net force = Applied Force - μ*Normal Force
where μ is the coefficient of kinetic friction
Normal Force = Force due to gravity = mass*gravity
Normal Force = (210 kg)(9.81 m/s²) =<em> 2,060.1 N</em>
Then,
Net force = 4100 - 0.38*2060.1 = 3317.162 N
3317.162 N = (210 kg)(a)
Solving for acceleration,
<em>a = 15.796 m/s²</em>
B. Density. I hope this helps!