All categories

2 years ago

Based on the free-body diagram, the net force acting on this firework is

Physics

2 answers:

Strike441 [17]2 years ago

4 0

0N. The net force acting on this firework is 0.

The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.

Based on the free-body diagram, we have:

The force of gases is Fgases = 9,452N

The force of the rocket Frocket = -9452

Then, the net force acting is:

Fnet = Fgases + Frocket

Fnet = 9,452N - 9,452N = 0N

Gnom [1K]2 years ago

4 0

Answer:

0 on edge !!!

You might be interested in

Identify the Following as physical properties or chemical properties.

sveticcg [70]

A.) is chemical, B.) is physical, C.) is physical, D.) is chemical, E.) is physical, F.) is physical, G.) is physical, and H.) is chemical.

5 0

2 years ago

Read 2 more answers

A mass is placed at the end of a spring. It has starting velocity of V & allowed to oscillate freely. If the mass has a star

LiRa [457]

Answer:

Equation for SHM can be written

V = w A cos w t where w is the angular frequency and the velocity is a maximum at t = 0

V1 = w1 A cos w1 t

V2 = w2 A cos w2 t

V2 / V1 = w2 / w1 since cos X t = 1 if t = zero

V2 / V1 = 2 pi f2 / (2 pi f1) = f2 / f1 = T1 / T2

If the velocity is twice as large the period will be 1/2 long

8 0

1 year ago

What does a trench form?What happens here?

Vinvika [58]

A hole, and people die if they fall in there.

8 0

2 years ago

Why the center of Newton rings is dark?

RideAnS [48]

The point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created in the center.

3 0

2 years ago

Read 2 more answers

A particle with charge q, mass m, and initial speed v0 in the x direction enters a region where the electric field is uniform in

Nezavi [6.7K]

Answer:

S = 1/2 Vo t + 1/2 a t^2 = d time for particle to travel distance d

F = E q force acting on particle

a = F / m = E q / m

d = Vo t + E q / (2 m) t^2

One would need to solve the quadratic equation shown to find the time t

t^2 + (2 m) / E q * V0 t - (2 m) / E q * d = 0

or t^2 + A V0 t - A d = 0 where A = (2 m) / E q

8 0

1 year ago