Answer:
(a) The work required to move the crate = 7150 J
(b) The Work required to move the crate vertically = 6000 J
Explanation:
(a) Frictional Force: These is the force that tend to oppose the motion of two bodies in contact.
Work required to move the crate = work done against friction + work required to move it through a distance of 5.0 m.
Wr = Wf + Wd
Where Wr = work required to move the crate, Wf = work done against friction, Wd = work required to move the crate through 5.0 m
Given: Wf = friction force × distance = 230×5 = 1150 J
and Wd = force × distance = 1200×5.0 =6000 J.
Substituting these values into equation 1
Wr = 6000 + 1150
Wr = 7150 J
Therefore the work required to move the crate = 7150 J
(b)
Work required to move the crate vertically = mgh
or
Work required to move the crate vertically = Wh................ Equation 2
Where W = weight of the block, h = vertical height
<em>Given:W = 1200 N, h= 5.0 m</em>
Substituting these values into equation 2
Work required to move the crate vertically = 1200×5
Work required to move the crate vertically = 6000 J
