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aliya0001 [1]
2 years ago
9

Can someone help me please ? It would be greatly appreciated:-)

Mathematics
1 answer:
WITCHER [35]2 years ago
7 0
I think it might be a ? it sounds the most reasonable .
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If we wanted to know how high a 5th-grade student could jump, how many students would be reasonable to test? 5, 12, 30, or 200.
77julia77 [94]
The right amount to test would be 30.

200 is to many kids and 12 is not enough.

Hope this Helps!!
4 0
3 years ago
A candidate took a phone poll of 110 people. Of the 110 people polled, 87 said they would vote for the other person. There are 9
SSSSS [86.1K]

Option B

7569 number of people are going to vote for the other candidate

<em><u>Solution:</u></em>

Given that candidate took a phone poll of 110 people

Of the 110 people polled, 87 said they would vote for the other person

There are 9570 people in the district

You can set up this problem like a proportion

Let "x" be the number of people who would vote for the other candidate

\frac{87}{110} = \frac{x}{9570}

To solve proportions, you cross-multiply. This means you multiply the numerator by the other denominator, and the denominator by the other numerator

87 \times 9570 = 110 \times x

832590 = 110x

x = 7569

Thus 7569 number of people are going to vote for the other candidate

6 0
3 years ago
Read 2 more answers
1. If x+ 2 = 7, then x=5.<br> Converse:<br> Inverse:<br> Contrapositive:
fenix001 [56]

Answer:

Converse: if 5=x then x+2=7

Inverse: if x+2 doesnt = 7 then x isnt 5

Contrapositive: if x doesnt equal five then x plus two doesnt equal seven

Step-by-step explanation:

We just did this last week :)

7 0
3 years ago
Read 2 more answers
A system of two linear equations and three unknowns can be solved by:
irakobra [83]
These cannot be solved.- 3 unknowns require 3 equations 
3 0
3 years ago
I'm stuck on number 1 can somebody help me out?please☺
yuradex [85]
You have to find the common denominator which is 4 and multiply 26 by 4 which equals 104 add 3 which is 107 and divide by 4


Answer:107/4
7 0
2 years ago
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