Answer:
Explanation:
which is the final velocity minus the initial velocity in the numerator, and the change in time in the denominator. For us:
so
a = .92 m/s/s (NOT negative because you're speeding up)
Answer:
X = 5.48 mm
Explanation:
for single slit
By Rayleigh criterian
where d = slit width =0.5 mm
wavelength
therefore maximum of value of X can be calculated from above
X = 5.48 mm
Answer:
The speed at the end of the track = 27 m/s
The acceleration = 1.2 m/s²
Please find the Δx vs Δt, v vs Δt, a vs Δt
Explanation:
We have;
x = u·t + 1/2·a·t²
Where;
x = The distance = 300 m
u = The initial velocity = 0 m/s (Ball at rest)
t = The time taken = 22.4 s
Therefore;
300 = 0 + 1/2×a×22.4²
a = 2×300/22.4² = 1.19579 ≈ 1.2 m/s²
v = u + a×t
∴ v = 0 + 1.2 × 22.4 = 26.88 ≈ 27 m/s
Part of the table of values is as follows;
t, x, v
0, 0, 0
0.4, 0.095663, 0.478316
0.8, 0.382653, 0.956632
1.2, 0.860969, 1.434948
1.6, 1.530611, 1.913264
2, 2.39158, 2.39158
2.4, 3.443875, 2.869896
2.8, 4.687497, 3.348212
3.2, 6.122445, 3.826528
3.6, 7.748719, 4.304844
Answer:
4 %
Explanation:
mass of the object 1, m₁ = 0.1 Kg
initial velocity of object 1,v₁= 0.2 m/s
mass of object 2, m₂ = 0.15 kg
initial speed of the object 2. v₂ = 0 m/s
Kinetic energy retained by the object 1 = ?
using the formula to calculate velocity of the ball after collision
negative sign represent the velocity is in opposite direction after collision.
Initial KE
final KE
% of KE retained
=
=
= 4 %
the percentage of Kinetic energy retained after collision is equal to 4 %