Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]
X' = U - X
= {1,2,3,4,5,6} - {1,4,5}
= {2,3,6}
(ZUX') = {2,3,5} U {2,3,6}
= {2,3,5,6}
(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}
= {2}
Answer:7=0.5 |x-4| -3
+3 +3
10=0.5 |x-4|
10/0.5=0.5/0.5 |x-4|
20=|x-4|
^
-20=x-4 20=x-4
+4 +4 +4 +4
-16=x 24=x
The answers are -16=x and 24=x
Hope this helps, an if it pleases you put as the brainliest answer
Answer:
Prime.
Step-by-step explanation:
![x^2-7x+8\\](https://tex.z-dn.net/?f=x%5E2-7x%2B8%5C%5C)
First let's multiply our outer coefficients in this case 1 and 8, so we have 1x8=8. Now the point of this is to get the factors of 8 and see if we can get that middle term -7. Factors of 8 are 1x8, 2x4 and that's it. From there I notice that -8+1 = -7 and so:
![x^2-7x+8 = x^2-8x+x+8 = x(x-8)+(x+8)](https://tex.z-dn.net/?f=x%5E2-7x%2B8%20%3D%20x%5E2-8x%2Bx%2B8%20%3D%20x%28x-8%29%2B%28x%2B8%29)
Notice that the (x-8) and (x+8) are not the same factors, therefore the factors are not any of those answer choices and so it's prime. You can calculate the factors by using the quadratic formula, however I think that is beyond the scope of this question.
5x+9 =14
14 -6=8
8•2 = 14
So they answer is 14