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3 years ago

What is the equilibrium constant expression for the ksp of sr3(po4)2?

Chemistry

2 answers:

Eddi Din [679]3 years ago

7 0

The equilibrium constant expression for KSP of Sr3(PO4)2 is

KSP={(Sr^2+)^3 (PO4^3-)^2/ Sr3(PO4)2}

Explanation

write the ionic equation for Sr3(PO4)2

Sr3(PO4)2 → 3Sr^2+ + 2 PO4^3-

KSP is given by (concentration of the products raised to their coefficient /concentration of reactants raised to their coefficient)

Pie3 years ago

6 0

The equilibrium constant expression for KSP of Sr3(PO4)2 is

KSP={(Sr^2+)^3 (PO4^3-)^2/ Sr3(PO4)2}

Explanation

write the ionic equation for Sr3(PO4)2

Sr3(PO4)2 → 3Sr^2+ + 2 PO4^3-

KSP is given by (concentration of the products raised to their coefficient /concentration of reactants raised to their coefficient)

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When a lithium ion and nitrate ion combine, the result is:

maxonik [38]

LiNO3; nitrate has a charge of -1, and lithium has a charge of +1

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3 years ago

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A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott

Kipish [7]

Answer:

$\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}$

Given:

Mass = 14.0 g

Density ( $\rho$ ) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

$\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}$

Substituting value of m & density in the formula:

$\sf \implies 1.38 = \frac{14.0}{V} \\ \\ \sf \implies V = \frac{14.0}{1.38} \\ \\ \sf \implies V = 10.14 \ cm^3$

$\therefore$

Volume of the plastic used to make water bottle = 10.14 cm³

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3 years ago

Pure research becomes ___ when scientists develop a hypothesis based on the data and try to solve a specific problem

Inessa05 [86]

Answer:

The answer is applied research

Explanation:

Pure research becomes applied research when scientists develop a hypothesis based on the data and try to solve a specific problem.

This is because the pure research try to understand, predict or explain the behavior of different phenomena (the data) while the applied research try to develop new technologies or methods (hypothesis) to take part, intervene and/or create changes on these phenomena and solve a specific problem.

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3 years ago

Alright, now you actually have an aqueous solution of your salt! Though perhaps not all of the salt has dissolved yet, but we'll

erica [24]

If not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

<h3>What is concentration?</h3>

The concentration is the amount of substance that is present in solution. We know that we can not measure the concentration unless all of the solute have been dissolved in the solution.

Thus, if not all of the salt has dissolved then the measurement of the concentration at the time is really inaccurate.

Learn more about concentration:brainly.com/question/10725862

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1 year ago

How many moles of oxygen atoms are present in 30.5 grams of hydrogen peroxide (h2o2)?

Pepsi [2]

1.8 moles of oxygen atoms are present in 30.5 grams of hydrogen peroxide.

Explanation:

First we have to convert the given weight of hydrogen peroxide to molar mass of hydrogen peroxide. So for this, we have to divide the given weight with the molecular mass of hydrogen peroxide.

$\text {Molecular mass of } \mathrm{H}_{2} \mathrm{O}_{2}=(2 \times 1)+(2 \times 16)=2+32=34 \mathrm{g}$

So,

$\text {Molar mass of } \mathrm{H}_{2} \mathrm{O}_{2}=\frac{30.5}{34}=0.90 \text { moles of } \mathrm{H}_{2} \mathrm{O}_{2}$

Second step, in this moles, 2 molecules of oxygen are present. Thus 1 mole of Hydrogen peroxide consists of 2 moles of oxygen. Then,

$0.90 moles of $\mathrm{H}_{2} \mathrm{O}_{2}=2 \times 0.90=1.8$ moles of oxygen$

So, 30.5 grams of hydrogen peroxide consists of 1.8 moles of oxygen.

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2 years ago