I only knwi one way which is if water evaporates from a mixture
The volume (in mL) of methylergonovine the nurse should draw up in the syringeis is 0.25 mL
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
With the concept of density, we can obtain the volume of methylergonovine. Details below
<h3>How to determine the volume </h3>
The following data were obtained from the question:
- Mass of methylergonovine = 0.2 mg
- Density of methylergonovine = 0.8 mg/mL
- Volume of methylergonovine =?
Density = mass / volume
Cross multiply
Density × volume = mass
Divide both sides by density
Volume = mass / density
Volume = 0.2 / 0.8
Volume of methylergonovine = 0.25 mL
Learn more about density:
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Answer : The specific heat of the metal is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of metal = ?
= specific heat of water = 
= mass of metal = 97 g
= mass of water = 122 g
= final temperature of mixture = 
= initial temperature of metal = 
= initial temperature of water = 
Now put all the given values in the above formula, we get
Therefore, the specific heat of the metal is,
Answer:
1.7 mL
Explanation:
<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>
Step 1: Calculate [H⁺] in the dilute solution
We will use the following expresion.
pH = -log [H⁺]
[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M
Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.
Step 2: Calculate the volume of the concentrated HCl solution
We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂/C₁
V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL
