Molecules with a plane of symmetry between the chiral centers are achiral and meso. From the given molecules (Picture attached) only (A) compound 1 is meso.
When compounds possess a plane of symmetry between the chiral centers they are called achiral or meso compounds. Among the given compounds (A) compound 1 have a plane of symmetry. So we can say compound one is a meso or achiral compound. Compounds two, three, and four have no plane of symmetry, as you can see in the structures attached. So all other compounds (compound 2, compound 3, and compound 4) except compound one are not meso or achiral.
You can also learn about meso compounds from the following question:
brainly.com/question/29022658
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The correct answer is approximately 1.95g. First, take (1.022*10^10)/(1.277*10^9). This is the same as time elapsed/half-life. This gives you 8, which is the number of half lives. Then multiply mass (500.3g) by (1/2)^8, resulting in 1.95g, which is the answer.
Absolute zero is the point at which the fundamental particles of nature have minimal vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion.
Hope this helped! c:
Answer: Option (d) is the correct answer.
Explanation:
Thermal energy is defined as the internal energy of an object because of the kinetic energy present within the molecules of the object.
So, when thermal energy is added to an object then kinetic energy within its molecules will also increase. As a result, temperature of the object will also increase due to increase in number of collisions between the molecules.
Therefore, we can conclude that the statement energy that is associated with temperature, describes thermal energy.
I am assuming that the problem ask for the pressure in
the system. To be able to calculate this, we first assume that the system acts
like an ideal gas, then we can use the ideal gas equation to find for pressure
P.
P V = n R T
where,
P = Pressure (unknown)
V = 0.17 m^3
n = moles of lng / methane
R = gas constant = 8.314 Pa m^3 / mol K
T = 200 K
We find for the moles of lng. Molar mass of methane = 16
kg / kmol
n = 55 kg / 16 kg / kmol
n = 3.44 kmol CH4 = 3440 mol
Substituting all the values to the ideal gas equation:
P = 3440 mol * (8.314 Pa m^3 / mol K) * 200 K / 0.17 m^3
P = 33,647,247 Pa
<span>P = 33.6 MPa</span>
