1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr1967 [171]
3 years ago
10

The deflection of alpha particles in Rutherford’s gold foil experiments resulted in what change to the atomic model?

Chemistry
2 answers:
Strike441 [17]3 years ago
5 0
Hello.

This experiment proved that atoms are not massive, they have large blanks inside the structure. Therefore, models like Thomsom's and Dalton's weren't good enough to describe the comportment of these units. A model of an atom like a <em>planetary system</em> was elaborated after this. 
STALIN [3.7K]3 years ago
4 0

Rutherford performed the gold foil experiment and the observation was as follows:

  • Most of the alpha particles passed undeflected through the atom proving that most of the atom is empty space.  
  • A certain fraction of alpha particles deflected by 90 degrees that indicated the center of the atom is positive.  
  • Another small fraction of alpha particles deflected by more than 90 degrees that indicated that most of the atom's mass lies in a small volume at the center of the atom.  

You might be interested in
What is the product of radioactive decay He called?
Zinaida [17]

Answer:

Alpha, Beta, and Gamma particles according to ability to penetrate matter.

Explanation:

  • Alpha represent the largest particle which penetrates the least with a positive charge,
  • Beta particles carry a negative charge, and
  • Gamma rays are neutral.
3 0
3 years ago
Pleaseeee helpppp thank youu​
Gemiola [76]

<em>Answer:</em>

<h3><em>Answer:</em><em> </em><em>well</em><em> </em><em> </em></h3>

<em>b. a type of gas is evolved ( hydrogen gas</em><em> )</em>

<em> </em>

5 0
2 years ago
Since density depends on the mass and volume of an object, we need both of these values combined in the correct way to solve for
alukav5142 [94]

Answer:

  7.86 g/cm³

Explanation:

  11.0 kg = 11,000 g

The density in g/cm³ is ...

  (11,000 g)/(1,400 cm³) = 7.86 g/cm³

7 0
3 years ago
Help me with please !!!
egoroff_w [7]

I would think the last one about the ozone layer
6 0
3 years ago
What model did Rutherford make??
Rainbow [258]
A model of the atom devised by Ernest Rutherford.
6 0
3 years ago
Other questions:
  • The following Lewis diagram represents the valence electron configuration of a main-group element. This element is in group 2A A
    13·1 answer
  • Can I+ (the iodine cation) becalled a Lewis base?<br> Fullyexlplain your answer.
    14·1 answer
  • In the wave mechanical model of the atom orbitals are regions of the most probable location of
    12·1 answer
  • PLEASE HELP ME WITH THE CORRECT ANSWER
    10·1 answer
  • 19. Chemical properties can be used to
    14·1 answer
  • What is the product of ( 2.324 cm x 1.11 cm) expressed to the correct number of significant figures?
    10·1 answer
  • Why do we consider diamonds a kind of metamorphic rock?
    9·1 answer
  • I’m completely lost on these stoichiometry problems
    7·2 answers
  • How do I balance coefficient equations
    11·2 answers
  • PLZ Help i need to turn it in before Friday ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!