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Aleks [24]
2 years ago
13

How many protons, neutrons, and electrons are in the isotope 32S2-

Chemistry
1 answer:
Snezhnost [94]2 years ago
7 0

Answer:

There are 16 protons, 18 electrons and 16 neutrons. I hope this helped:)

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Calculate the density of a solid in g/cm3 if it weighs 38.3 kg and has a volume of 0.00463 m3.
RideAnS [48]

Answer: D=8.27 g/cm³

Explanation:

Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.

D=\frac{38.3kg}{0.00463m^3} *\frac{(1m)^3}{(100cm)^3} *\frac{1000g}{1kg}

With this equation, the m³ and kg cancel out, and we are left with g/cm³.

D=8.27 g/cm³

3 0
3 years ago
The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way:
LiRa [457]

Explanation:

(a)  As the given chemical reaction equation is as follows.

           OCl^{-} + I^{-} \rightarrow OI^{-1} + Cl^{-1}

So, when we double the amount of hypochlorite or iodine then the rate of the reaction will also get double. And, this reaction is "first order" with respect to hypochlorite and iodine.

Hence, equation for rate law of reaction will be as follows.

              Rate = K \times [OCl^{-}] \times [l^{-}]

(b)  Since, the rate equation is as follows.

                    Rate = K [OCl^{-}][l^{-}]

Let us assume that ([OCl^{-}] = [l^{-}])

Putting the given values into the above equation as follows.

             1.36 \times 10^{-4} = K \times (1.5 \times 10^{-3})^2

            1.36 \times 10^{-4} = K \times (2.25 \times 10^{-6})

                   K = \frac{1.36 \times 10^{-4}}{2.25 \times 10^{-6}}

                      = 60.4 M^{-1}sec^{-1}

Hence, the value of rate constant for the given reaction is 60.4 M^{-1}sec^{-1} .

(c) Now, we will calculate the rate as follows.

                Rate = K [OCl^{-}][l^{-}]

                         = 60.4 \times (1.8 \times 10^{3}) \times (6.0 \times 10^{4})

                        = 6.52 \times 10^{5}

Therefore, rate when [OCl^{-}] = 1.8 \times 10^{3} M and [I^{-}]= 6.0 \times 10^{4} M is  6.52 \times 10^{5}.

8 0
3 years ago
I need help with this ASAP
NNADVOKAT [17]

Answer: I dunno that but u should give me brainliest

Explanation:

5 0
2 years ago
A container is filled with a mixture of gases:
strojnjashka [21]

Answer:

The partial pressure of chlorine gas in the mixture is 1.55 atm.

Explanation:

Partial pressure of oxygen gas = p_1=1.0 atm

Partial pressure of nitrogen gas = p_2=0.75 atm

Partial pressure of chlorine gas = p_3=?

Total pressure of the mixture of gases = P = 3.30 atm

Using Dalton's law of partial pressure:

P=p_1+p_2+p_3

3.30 atm=1.0 atm+ 0.75 atm+p_3

p_3=3.30atm - (1.0 atm+ 0.75 atm)=1.55 atm

The partial pressure of chlorine gas in the mixture is 1.55 atm.

8 0
3 years ago
A sample of gas has a volume of 12.0 L and a pressure of 2.00 ATM. If the pressure of gas is increased to6.00 ATM, what is the n
earnstyle [38]

Answer:

4L

Explanation:

8 0
3 years ago
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