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Y_Kistochka [10]
2 years ago
15

For each of the following compounds, state whether it is ionic or covalent. If it is ionic, write the symbols for the ions invol

ved:
(A) NF3
(B) BaO
(C) NH4)2CO3
(D) Sr(H2PO4)2
(E) IBr
(F) Na2O
Chemistry
1 answer:
Elden [556K]2 years ago
5 0

(A) NF3 covalent compound

(B) BaO ionic bond.

(C) NH4)2CO3 ionic bond.

(D) Sr(H2PO4)2 covalent compound

(E) IBr covalent compound

(F) Na2O  ionic bond.

<h3>What are a covalent compound and ionic bond?</h3>

Covalent bonds form when two or more additional nonmetals combine. For instance, both hydrogen and oxygen are nonmetals, and when they connect to make moisture, they do so by forming covalent bonds. Combinations that are composed of only non-metals or semi-metals with non-metals will demonstrate covalent bonding and will be classified as molecular combinations.

  • As a broad rule of thumb, combinations that involve a metal binding with either a non-metal or a semi-metal will show ionic bonding. Therefore, the compound created from sodium and chlorine will be ionic (a metal and a non-metal). Nitrogen monoxide (NO) will be a covalently bound molecule (two non-metals), silicon dioxide (SiO2) will be a covalently bound molecule (a semi-metal and a non-metal) and MgCl2 will be ionic (a metal and a non-metal).
  • A polyatomic ion is an ion comprised of two or more particles that have a commission as a group (poly = many). The ammonium ion (see figure below) consists of one nitrogen atom and four hydrogen atoms. Concurrently, they constitute a single ion with a 1+ charge and a formula of NH4+. The carbonate ion (see figure below) consists of one carbon particle and three oxygen atoms and maintains a comprehensive charge of 2−. The procedure of the carbonate ion is CO32−.

To learn more about covalent compound, refer to:

brainly.com/question/3447218

#SPJ9

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How much heat (in kJ k J ) is evolved in converting 2.00 mol m o l of steam at 135 ∘C ∘ C to ice at -42 ∘C ∘ C ? The heat capaci
vovikov84 [41]

The total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

<h3>Heat evolved in converting the steam to ice</h3>

The total heat evolved is calculated as follows;

Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)

where;

  • Q is heat evolved

Q = = mcΔθ

where;

  • m is mass,  (mass of water = 18 g/mol)
  • c is specific heat capacity,
  • Δθ is change in temperature

Q(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)

Q(tot) = -12,928.68 J

Thus, the total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

Learn more about heat here: brainly.com/question/13439286

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8 0
2 years ago
Tarnished silver can be cleaned with toothpaste. Give reason
vfiekz [6]
Toothpaste is an abrasive that contains many things, but mainly phosphates.
6 0
3 years ago
Please Help mE!!!!!!!!!!!!!!!!!!!!!!
JulijaS [17]
The answer is an ENDOTHERMIC REACTION.
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8 0
3 years ago
Read 2 more answers
Murcury is the only metal at room temperature. Its density is 13.6g/mL. How many grams of murcury will occupy a volume of 95.8mL
Hatshy [7]

Answer:

<h3>The answer is 1.30288 × 10³ g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 95.8mL

density = 13.6g/mL

We have

mass = 13.6 × 95.8 = 1302.88

We have the final answer as

<h3>1.30288 × 10³ g</h3>

Hope this helps you

3 0
3 years ago
A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori
Nitella [24]

Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of metal = 129.00 g

m_2 = mass of water = 45.00 g

T_f = final temperature = 39.6^oC

T_1 = initial temperature of metal = 97.8^oC

T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

c_1=0.481J/g^oC

Therefore, the specific heat of metal is 0.481J/g^oC.

4 0
3 years ago
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