A blue die and green die are rolled find the probability that the sum is 12

Systolic Blood Pressure Assume that the mean systolic blood pressure of normal adults is 120 millimeters of mercury and the stan

liq [111]

Answer:

0.1425 = 14.25% probability that the individual's pressure will be between 119.4 and 121.4mmHg.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 120, \sigma = 5.6$

Find the probability that the individual's pressure will be between 119.4 and 121.4mmHg

This is the pvalue of Z when X = 121.4 subtracted by the pvalue of Z when X = 119.4. So

X = 121.4

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{121.4 - 120}{5.6}$

$Z = 0.25$

$Z = 0.25$ has a pvalue of 0.5987

X = 119.4

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{119.4 - 120}{5.6}$

$Z = -0.11$

$Z = -0.11$ has a pvalue of 0.4562

0.5987 - 0.4562 = 0.1425

0.1425 = 14.25% probability that the individual's pressure will be between 119.4 and 121.4mmHg.

8 0

3 years ago

12 of the 28 dogs at the shelter are purebred what percent of the dogs are pure breed?HELP!

harina [27]

Answer:

57.142%

Step-by-step explanation:

28-12=16

16/28*100=57.142%

3 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

What's the sum off 663 and 23

vlada-n [284]

Answer: 686

Step-by-step explanation: 663 + 23 = 686

8 0

2 years ago

Tim drives at an average of 80km

guapka [62]

Answer:

80km --- 49.7097mi

Step-by-step explanation:

thats quite slow... but please provide context then i can solve it for you

7 0

3 years ago

A blue die and green die are rolled find the probability that the sum is 12​

A blue die and green die are rolled find the probability that the sum is 12