Answer:
When a male pig from a line of true-breeding (homozygous) black, solid-hooved pigs was crossed to a female from a breed (homozygous) of red, cloven-hooved pigs, their several progeny all looked alike with regard to color and hooves. These progeny were all mated to members of the same breed as their red, cloven-hooved mother pig. The offspring from this final cross were: 11 black, cloven-hooved; 8 black, solid-hooved; 14 red, cloven-hooved; and 10 red, solid-hooved. For each of these two genes (coat color and hoof type) determine which allele is the dominant one. Explain your reasoning. What were the phenotypes of the progeny produced by the first mating in this problem.
I think it’s So lipid-soluble molecules do not enter or exit the plasma membrane unassisted
Hope this helps so sorry in advance if it’s wrong but hope it helps
Attached is the image of the concerned ECG reading.
In reading the ECG, first you read the heart rate. To read the heart rate, you must count for the number of small boxes in between QRS complexes, specifically R-R intervals. These number of small boxes will then be used to divide 1500. In this example, there are 20 small boxes between R-R intervals. 1500 divided by 20 is 75, so the heart rate of this ECG reading is 75 beats per minute.
<em>Another way, albeit less accurate, is to count the big squares between R-R intervals and instead of dividing it by 1500, you divide it by 300.</em>