A rubber ball with mass 0.20 kg is dropped vertically from a height of 1.5 m above a floor. The ball bounces off of the floor, a
nd during the bounce 0.60 J of energy is dissipated. What is the maximum height of the ball after the bounce
2 answers:
Answer:
The maximum height of the ball after the bounce is 1.2 m
Explanation:
Potential Energy = mass * Height * acceleration of gravity
PE=mgh
= 0.2 x 9.8 x 1.5
P.E = 2.94 J
During bounce of ball 0.60 J of energy is lost. So
2.94 - 0.6 = 2.34 J
now new energy is 2.34
New P.E = mgh
2.34 = 0.2 x 9.8 x h
h = 2.34 / 0.2 x 9.8
h = 1.2 m
The maximum height of the ball after the bounce is 1.2 m
Explanation:
Given:
Mass = 0.2 kg
Height = 1.5 m
Potential energy of the drop, PE = m × g × h
= 0.2 x 9.81 x 1.5
= 2.94 J
After the drop, 0.6 J of energy is dissipated, so amount of energy left
= 2.94 - 0.6
= 2.34 J
This energy is eqal to thenew potential energy which is:
m × g × h = 2.34
0.2 × 9.81 × h = 2.34
= 2.34/1.962
= 1.19 m.
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