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GalinKa [24]
3 years ago
12

How do you find period when you have frequency

Physics
1 answer:
nydimaria [60]3 years ago
8 0

Period and frequency are mutual reciprocals.

Period = 1 / frequency .

Frequency = 1 / period

(Frequency) x (Period) = 1


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Time dilation: A missile moves with speed 6.5-10 m/s with respect to an observer on the ground. How long will it take the missil
tatyana61 [14]

Answer:

The time taken by missile's clock is 4.6\times 10^{6} s

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As per the question:

Speed of the missile, v_{m = 6.5\times 10^{3}} m/s

Now,

If 'T' be the time of the frame at rest then the dilated time as per the question is given as:

T' = T + 1

Now, using the time dilation eqn:

T' = \frac{T}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

\frac{T'}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

\frac{T + 1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

1 + \frac{1}{T} = \frac{1}{\sqrt{1 + (\frac{v_{m}}{c})^{2}}}

1 + \frac{1}{T} = (1 + (\frac{v_{m}}{c})^{2})^{- \frac{1}{2}}         (1)

Using binomial theorem in the above eqn:

We know that:

(1 + x)^{a} = 1 + ax

Thus eqn (1) becomes:

1 + \frac{1}{T} = 1 - \frac{- 1}{2}.\frac{v_{m}^{2}}{c^{2}}

T = \frac{2c^{2}}{v_{m}^{2}}

Now, putting appropriate values in the above eqn:

T = \frac{2(3\times 10^{8})^{2}}{(6.5\times 10^{3})^{2}}

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4 0
3 years ago
A battery-operated car moves forward as a result of which device? Electromagnet, generator, motor, or a transformer?
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A battery-operated car moves forward as a result of which device?

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2 years ago
A current of 0.5 A flows in a 60 W light bulb when the voltage differences between the ends of the filament is 120 V. What is th
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Resistance = (voltage) / (current)

Resistance = (120 V) / (0.5 A)

<em>Resistance = 240 ohms</em>

<em></em>

Know what ?  There might be too much information given in this question.  I want to check, because it's possible that it might not even all fit together.

To calculate my answer, I only used the voltage and the current.  I didn't use the "60 watts", and I'm curious to know whether it even fits with the given voltage and current.

Power = (voltage) times (current).

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Power = 60 watts  

Well gadzooks and sure enough !  The three numbers given in the question all go together nicely.  

And not only THAT !

The answer could have been calculated by using ANY TWO of them.

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Answer:

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