Answer:
1.5 A
Explanation:
Applying
V = IR'....................... Equation 1
make I the subject of the equation
I = V/R'.................. Equation 2
Where V = Voltage, I = current, R' = Total resistance.
From the question,
In a series connection,
R' = 0.2+0.3+0.5+5 = 6 ohm.
Given: V = 9V
Substitute into equation 2
I = 9/6
I = 1.5 A.
Note: Since all the resistors are connected in series, thesame current flows through them
Therefore the current flowing through the 5 ohm resistor = 1.5 A
Answer: c. increased sensitivity to ADH
Explanation:
a. a decline in the number of functional nephrons: With aging the loss of nephron occurs that can be detected by the age related decrease in the glomerular filteration rate.
b. a reduction in the GFR (glomerular filtration rate): The GFR tend to decline in older age even though there is no disease. These people are required to check with the GFR in future.
d. problems with the micturition reflex: With aging people experience problem of bladder control. This leads to leakage or incontinence of urine or urinary retention that is inability to empty the bladder.
e. loss of sphincter muscle tone: With age the sphincter tone may diminish. This results in loss of control and storage capacity. The rectal muscles or sphincter muscles get loose which lead to passage of stool before reaching the washroom.
Divide the distance by the speed:
(18 m) / (42 m/s) = 3/7 s ≈ 0.43 s
Answer:
The coefficient of static friction between the box and floor is, μ = 0.061
Explanation:
Given data,
The mass of the box, m = 50 kg
The force exerted by the person, F = 50 N
The time period of motion, t = 10 s
The frictional force acting on the box, f = 30 N
The normal force on the box, η = mg
= 50 x 9.8
= 490 N
The coefficient of friction,
μ = f/ η
= 30 / 490
= 0.061
Hence, the coefficient of static friction between the box and floor is, μ = 0.061