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3 years ago

Calculate the potential energy of a 5.2 kg object positioned 5.8 m above the ground.

Physics

2 answers:

GrogVix [38]3 years ago

4 0

Answer:

295.568J

Explanation:

use P=mgh

plug in givens

P= 5.2*9.8*5.8= 295.568J

Free_Kalibri [48]3 years ago

3 0

$\bf \huge \hookrightarrow \:Given :$

$\bf \implies \: Weight \: \: of \: \: Object \: = 5.2 \: kg$

$\bf \implies \: Height \: = 5.8m$

$\bf \huge \hookrightarrow \:To \: \: Find$

<h3> ☛ Potential Energy of object.</h3>

$\bf \Large \hookrightarrow \:Formula \: \: using$

$\Large \mid \underline {\bf {{{\color{orange}{p \: = \: mgh}}}}} \mid$

P denotes Potential Energy

m denotes mass

g denotes gravitational field

h denotes height

<h3>☛ Now , putting the values in formula.</h3>

We know that , the gravitational field of earth is 9.8.

$\bf \Large \mapsto \: \: 5.2 \: \times 9.8 \: \times 5.8 \\ \\ \bf \Large \mapsto \: \: 50.96 \: \times 5.8 \\ \\ \bf \Large \mapsto \: \: 295.56$

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3 years ago

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yawa3891 [41]

Answer:

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Explanation:

Given;

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3 years ago

The area of the tympanic membrane is 100 mm 2 and the area of the oval window is 5 mm 2 . if a sound wave applies 10 n to the ty

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<span>The answer is "0.5N".

According to the question;
P1=P2
so,
F1/A1= F2/A2

P=(F/A)

A1=100mm</span>²
<span>
F1= 10N

A2= 5mm</span>²
<span>
F2= ?

F2= ((F1 x A2)/A1)
= ((10 x 5) /100)

=50/100

=0.5N</span>

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