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goldenfox [79]
3 years ago
10

Ernest Rutherford's experiment led him to change the outlook on atom because

Chemistry
1 answer:
qaws [65]3 years ago
6 0

Answer:

What led him to change his outlook was because in his experiment, when he fired positively charged alpha particles at a piece of gold foil, he observed that some of the alpha particles were deflected to some degree, and some others bounced back directly toward him.

Explanation:

In his experiment, he fired positively charged alpha particles at a piece of gold foil.

Now, after doing that he observed that some of the alpha particles were deflected to some degree, and some others bounced back directly toward him.

After those observations, he felt that for the order of the alpha particles to have been deflected, they would possibly have been hit or come close to being hit by a positively charged particle in the atom. This made him to conclude that an atom consists mostly of empty space, with a very small and dense but positively charged nucleus at the center. And that this nucleus contains most of the mass of the atom, while the electrons orbit the nucleus.

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CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262)
Effectus [21]

Answer:CO2(g) will be formed at a faster rate in experiment 2 because more H+ particles can react per unit time

Explanation:

8 0
3 years ago
In a 100 g sample of iron(III) oxide, how many grams of iron are present?
e-lub [12.9K]
The formula of Iron(III) oxide is Fe2O3
In order to calculate the mass of iron in a given sample of iron(III) oxide, we must first know the mass percentage of iron in iron(III) oxide. This is calculated by:
[mass of iron in one mole of iron(III) oxide/ mass of one mole of iron(III) oxide] * 100 
= [(moles of iron * Mr of iron) / (moles of Iron * Mr of Iron + moles of Oxygen * Mr of Oxygen)] * 100
= [(2 * 56) / (2 * 56 + 3 * 16)] * 100
= (112 / 160) * 100
= 70%
Thus, in a 100g sample, the weight of iron will be:
100 * 70%
= 70 grams
8 0
4 years ago
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2p: n=2. l=1

6 0
3 years ago
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