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Which is the anode (oxidation) and cathode (reduction)?

arsen [322]

Answer:

2H+ + 2e - ---> H2(g) is the cathode

2Cl - ---> Cl2(g) + 2e - is the anode

Explanation:

Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.

8 0

2 years ago

A particular reactant decomposes with a half-life of 121 s when its initial concentration is 0.357 M. The same reactant decompos

S_A_V [24]

Answer : The value and unit of the rate constant for this reaction is, $2.31\times 10^{2}$ and $M^{-1}s^{-1}$ respectively.

Explanation :

As we know that half-life of zero-order and second-order reaction depend on the concentration of reactant while the half-life of first-order reaction is independent of the concentration of the reactant.

The expression of half-life for zero order reaction:

$t_{1/2}=\frac{[A_o]}{2k}$

The expression of half-life for first order reaction:

The expression of half-life for second order reaction:

$t_{1/2}=\frac{1}{[A_o]k}$

The given reaction can not be first order reaction because it is independent of the concentration of the reactant.

So, the given reaction can be zero order or second order.

First we have to calculate the value of rate constants for zero order.

$t_{1/2}=\frac{[A_o]}{2k}$

$121s=\frac{0.357M}{2k}$

$k=1.48\times 10^{-3}M/s$

and,

$t_{1/2}=\frac{[A_o]}{2k}$

$235s=\frac{0.184M}{2k}$

$k=3.92\times 10^{-4}M/s$

From this we conclude that the reaction can not be zero order.

Now we have to calculate the value of rate constants for second order.

$t_{1/2}=\frac{1}{[A_o]k}$

$121s=\frac{1}{(0.357M}\times k}$

$k=2.31\times 10^{2}M^{-1}s^{-1}$

and,

$t_{1/2}=\frac{1}{[A_o]k}$

$235=\frac{1}{(0.184M}\times k}$

$k=2.31\times 10^{2}M^{-1}s^{-1}$

From this we conclude that the reaction is a second order.

Therefore, the value and unit of the rate constant for this reaction is, $2.31\times 10^{2}$ and $M^{-1}s^{-1}$ respectively.

8 0

2 years ago

Use the following equation to determine the charge on iron when it dissociates from oxygen and determine whether it is being oxi

kumpel [21]

The correct answer is A. Brainliest would be much appreciated.

8 0

2 years ago

Assume the cup of tea has cooled off faster than the pot of tea. In which liquid would the molecules be moving faster and in whi

OLga [1]

In the pot of tea the molecules would be moving faster than in the cooled cup of tea. As liquid is heated the atoms vibrate faster which increases the distance between them. When heat leaves a substance, the molecules vibrate slower and get closer.

8 0

3 years ago

Read 2 more answers

Food travels directly from the stomach to the

OleMash [197]

From the stomach, the food travels to the small intestine. This happens with the help of a movement known as peristalsis. Juices are released in the small intestine, which helps in the breakdown of carbohydrates, starch, and proteins.

3 0

2 years ago