The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
Answer:
<h2>. A human diploid cell has 46 chromosomes in 23 pairs.</h2>
When water is transferred from land to atmosphere by evaporation from the soil and by transpiration plants.
I believe that the right answer is Heat energy
MRNA is read 5->3
Start codons can vary depending on the cell/organism type although more generally for mRNA it is always: AUG which is always Methionine
Stop codons for mRNA are:
<span>UAG ("amber") , UAA ("ochre"), <span>UGA ("opal")
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<span>5'-uaucc.aug.gca.cuu.uaa.ac-3'
M-A-L
Methionine-Alanine-Leucine
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