Force of gravity = Mass x Gravitational force
Fg=mg
Fg = (5.7)(9.8)
Fg= 55.86 N
Answer:
1.) 11 km/s
2.) 9.03 × 10^-5 metres
Explanation:
Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.
Electron q = 1.6×10^-19 C
Electron mass = 9.11×10^-31 Kg
(a) What is the speed of the electron 1.3 ns after entering this region?
E = F/q
F = Eq
Ma = Eq
M × V/t = Eq
Substitute all the parameters into the formula
9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19
V = 7.68×10^-18 /7.0×10^-22
V = 10971.43 m/s
V = 11 Km/s approximately
(b) How far does the electron travel during the 1.3 ns interval?
The initial velocity U = 64 km/s
S = ut + 1/2at^2
S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2
S =8.32×10^-5 + 7.13×10^-6
S = 9.03 × 10^-5 metres
Answer:
Option C. Both technicians A and B are correct
Explanation:
Vehicle-to-vehicle communications consists of a wireless network where automobiles send messages containing operational information such as speed, location, direction of travel, braking, and loss of stability.
Technician A is correct, there will be fewer traffic collision because each driver will have enough information about traffic flow and such information will be properly managed since they have been known before hand.
By letting out information, such as your location, direction of traffic, etc, there is loss of privacy. This can lead to a security threat on the part of the users
A meter is 100 meters. So a hundredth of a meter stick is a centimeter.<span />
