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baherus [9]
3 years ago
13

The mole fraction of oxygen in dry air near sea level is 0.20948. The concentration of

Physics
2 answers:
hram777 [196]3 years ago
6 0
N sub air = ( P ) ( V ) / ( R ) ( T ) 

<span>n sub air = ( 739 / 760 ) ( 1.000 ) / ( 0.08205 ) ( 28.5 + 273.2 ) </span>

<span>n sub air = 0.03928 mol per L </span>

<span>R = universal gas constant = 0.08205 atm - L per mol - deg K </span>

<span>Find moles O2 per liter : </span>
<span>--------------------------------------... </span>

<span>n sub O2 = ( y sub O2 ) ( n sub air ) </span>

<span>n sub O2 = ( 0.20948 ) ( 0.03928 ) </span>

<span>n sub O2 = 0.008228 moles O2 per L </span>

<span>Now apply Avogadro's Number to get the O2 molecules per liter : </span>
<span>--------------------------------------... </span>

<span>N sub O2 = ( n sub O2 ) ( N sub AVO ) </span>

<span>N sub O2 = ( 0.008228 ) ( 6.022 x 10^23 ) </span>

<span>N sub O2 = 4.96 x 10^21 O2 molecules per liter

It's C.

</span>
BlackZzzverrR [31]3 years ago
3 0
C,d,or e you can use the process of elimination to decide...
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When small, positively charged ball is moved close to a large, positively charged ball it would be pushed away from the large positively charged ball since they are both positively charged. One has to put in energy to try to move the small ball closer to the large ball. The closer one try to move it to the large ball, the more energy one has to put in, so the more electrical potential energy the small ball would have.

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A system of ideal gas at 22°C undergoes an ischoric process with an internal energy decrease of 4.30 × 10 3 4.30×103 J to a fina
Komok [63]

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Temperature = 22°C

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Using formula of the entropy

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pav-90 [236]

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In this problem therefore, this means that the thermal energy is transferred from the hot water to the cold water.

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