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3 years ago

The mole fraction of oxygen in dry air near sea level is 0.20948. The concentration of

2 answers:

6 0

N sub air = ( P ) ( V ) / ( R ) ( T )

n sub air = ( 739 / 760 ) ( 1.000 ) / ( 0.08205 ) ( 28.5 + 273.2 ) 

n sub air = 0.03928 mol per L 

R = universal gas constant = 0.08205 atm - L per mol - deg K 

Find moles O2 per liter : 
--------------------------------------... 

n sub O2 = ( y sub O2 ) ( n sub air ) 

n sub O2 = ( 0.20948 ) ( 0.03928 ) 

n sub O2 = 0.008228 moles O2 per L 

Now apply Avogadro's Number to get the O2 molecules per liter : 
--------------------------------------... 

N sub O2 = ( n sub O2 ) ( N sub AVO ) 

N sub O2 = ( 0.008228 ) ( 6.022 x 10^23 ) 

N sub O2 = 4.96 x 10^21 O2 molecules per liter

It's C.

BlackZzzverrR [31]3 years ago

3 0

C,d,or e you can use the process of elimination to decide...

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2 years ago

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Vlada [557]

Answer:

Calculate the ratio of the rates of ozone destruction by these catalysts at 20 km, given that at this altitude the average concentration of OH is about 100 times that of Cl and that the temperature is about -50 °C

Knowing

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T = -50 °C = 223 K

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Calculate the rate constant for ozone destruction by chlorine under conditions in the Antarctic ozone hole, when the temperature is about -80 °C and the concentration of atomic chlorine increases by a factor of one hundred to about 4 × 105 molecules cm-3

Knowing

Rate constants for the reactions of atomic chlorine and of hydroxyl radical with ozone are given by 3x $10^{-11} e^{-255/T}$ and 2x $10^{-12} e^{-940/T}$

T = -80 °C = 193 K

The reaction rate will be given by [Cl] [O3] 3x $10^{-11} e^{-255/193} = 8.21^{-12} [Cl] [O3]$

Than, the reaction rate of OH with O3 is

Rate = [OH] [O3] 2x $10^{-12} e^{-940/193} = 1.53^{-14} [OH] [O3]$

Considering these 2 rates we can realize the ratio of the reaction with Cl to the reaction with OH is 535 * [Cl] / [OH]

Than, considering the concentration of Cl increases by a factor of 100 to about 4 × $10^{5}$ molecules $cm^{-3}$ , the result will be that the reaction with OH will be 535 + (100 to about 4 × $10^{5}$ molecules $cm^{-3}$ ) times faster than the reaction with Cl

Explanation:

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2 years ago

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3 years ago