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bixtya [17]
3 years ago
10

All types of electromagnetic waves moves with speed of light in *

Physics
1 answer:
Fiesta28 [93]3 years ago
7 0

Answer:

in a vacuum

Explanation:

Electromagnetic waves are waves consisting of oscillations of electric and magnetic fields along a plane perpendicular to the direction of propagation of the wave (transverse waves)

Electromagnetic waves are the only waves being able to travel in a vacuum, since they do not need a medium to propagate.

In a vacuum, all electromagnetic waves travel at the same speed, called speed of light, whose value is:

c=3.0\cdot 10^8 m/s

The speed of the waves is actually reduced when they enter a medium, according to

v=\frac{c}{n}

where n is the refractive index of the medium.

Electromagnetic waves are also classified into 7 different types according to their wavelength. From shortest to longest wavelength, we have:

Gamma rays

X-rays

Ultraviolet

Visible light

Infrared

Microwaves

Radio waves

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Which of the following is a device that uses an inclined plane?
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Answer:

A and B

Explanation:

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A 40 Watt lightbulb is on for 3 minutes. How many joules of work does it do?
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Answer:

Explanation:

Power (p)= 40 watt

time (t)= 3 minutes = 180 seconds

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we know

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hope it helps :)

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3 years ago
. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to
d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

B = 5 \times 10^{-6} T

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

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here we we will find the magnetic field due to wire which is along x axis is given as

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now we have

B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}

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Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

i = 40 A

r = 2 m

now we have

B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}

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Since the two magnetic field is perpendicular to each other

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3 years ago
What force is required to accelerate a 1,100 kg car to 0.5 meters squared
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A 4.0-cm tall light bulb is placed at distance of 8.3 cm from a concave mirror having a focal length of 15.2 cm. Determine the i
scoundrel [369]

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replacing the values we obtain:

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We also add a picture to see the imagen formation for this case.

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3 years ago
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