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liubo4ka [24]
3 years ago
14

Obviously, we can make rockets to go very fast, but what is a reasonable top speed? assume that a rocket is fired from rest at a

space station in deep space, where gravity is negligible. assume that c = 3.00 108 m/s.
Physics
1 answer:
steposvetlana [31]3 years ago
3 0

 

I’ve answered this problem before and there were 2 parts in this problem.

The solution would be like this for this specific problem:

<span>A.    </span><span>Vf = Vi + Vex*ln(Mi / Mf) </span><span>
<span>0.002 * 3e8m/s = 0 + 2000m/s * ln(Mi / Mf) </span>
<span>300 = ln(Mi / Mf) </span>
<span>1.9e130 = Mi / Mf </span></span>

 

<span>B.    </span><span>4000m/s = 2000m/s * ln(Mi / Mf) </span><span>
<span>2 = ln(Mi / Mf) </span>
<span>7.389 = Mi / Mf </span>
<span>Mf = Mi / 7.389 = 0.135*Mi<span> </span></span></span>

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Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
Evgen [1.6K]

Answer:

Explanation:

In a L C R circuit, the average power is given by

P_{av}=V_{rms}I_{rms}Cos\phi

As given in the question

CosФ = R / Z

And we know that

V_{rms}=I_{rms}\times Z

So

P_{av}=I_{rms}\times Z\times I_{rms}\times \frac{R}{Z}

P_{av}=I_{rms}^{2}\times R

6 0
3 years ago
The AC voltage source is connected to an inductor and a resistor in series. If the frequency of the source is increased the curr
DaniilM [7]

Answer:

If the frequency of the source is increased the current in the circuit will decrease.

Explanation:

The current through the circuit is given as;

I = \frac{V}{Z}

Where;

V is the voltage in the AC circuit

Z is the impedance

Z = \sqrt{R^2 + X_L^2}

Where;

R is the resistance

X_L is the inductive reactance

X_L = ωL = 2πfL

where;

L is the inductance

f is the frequency of the source

Finally, the current in the circuit is given as;

I = \frac{V}{\sqrt{R^2 + (2\pi fL)^2} }

From the equation above, an increase in frequency (f) will cause a decrease in current (I).

Therefore, If the frequency of the source is increased the current in the circuit will decrease.

5 0
3 years ago
1.33 m^3 of fluid flows out of a pipe in 24.5 s. the fluid leaves the pipe at 3.55 m/s. what is the area of the pipe. (unit=m^2)
Margaret [11]

Answer:

0.015meter^{2}

Explanation:

Total volume of water coming out = 1.33meter^{3}

Also volume = Cross sectional area*Length covered

Length covered = Velocity *time

                           =24.5*3.55

                           =86.97 meter

Let the cross sectional area be A.

1.33 = 86.97*A

A =0.015meter^{2}

3 0
3 years ago
Read 2 more answers
A toroid has a square cross section with the length of an edge equal to the radius of the inner surface. The ratio of the magnit
Tasya [4]

Answer:

2

Explanation:

7 0
3 years ago
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A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How man
Ne4ueva [31]

Answer:  

A. α = - 1.047 rad/s²  

B. θ = 14.1 rad  

C. θ = 2.24 rev  

Explanation:  

A.  

We can use the first equation of motion to find the acceleration:

\omega_f = \omega_i + \alpha t  

where,  

ωf = final angular speed = 0 rad/s  

ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s  

t = time = 3 s  

α = angular acceleration = ?  

Therefore,

0\ rad/s = 3.14\ rad/s + \alpha(3\ s)  

<u>α = - 1.047 rad/s²</u>

B.  

We can use the second equation of motion to find the angular distance:

\theta = \omega_it +\frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3)^2  

<u>θ = 14.1 rad</u>

C.  

θ = (14.1 rad)(1 rev/2π rad)  

<u>θ = 2.24 rev</u>

6 0
3 years ago
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