We have that The Density and Volume is given as
The factors that affect Density are Mass and Volume
From the question we are told that
The piece of wood shown above has a mass of 20 grams.
Wood parameters
2cm
5cm
3cm
Generally the equation for the Volume is mathematically given as
Generally the equation for the Density is mathematically given as
Therefore the factors that affect Density are Mass and Volume
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Answer:
a) that laser 1 has the first interference closer to the central maximum
c) Δy = 0.64 m
Explanation:
The interference phenomenon is described by the expression
d sin θ = m λ
Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference
For the separation of the lines we use trigonometry
tan θ = sin θ / cos θ = y / x
In interference experiments the angle is very small
tan θ = sin θ = y / x
d y / x = m λ
a) and b) We apply the equation to the first laser
λ = d / 20
d y / x = m d / 20
y = m x / 20
y = 1 4.80 / 20
y = 0.24 m
The second laser
λ = d / 15
d y / x = m d / 15
y = m x / 15
y = 0.32 m
We can see that laser 1 has the first interference closer to the central maximum
c) laser 1
They ask us for the second maximum m = 2
y₂ = 2 4.8 / 20
y₂ = 0.48 m
For laser 2 they ask us for the third minimum m = 3
In this case to have a minimum we must add half wavelength
y₃ = (m + ½) x / 15
m = 3
y₃ = (3 + ½) 4.8 / 15
y₃ = 1.12 m
Δy = 1.12 - 0.48
Δy = 0.64 m
Answer:
This is because motion is intended to occur but at zero acceleration. It means at a constant velocity, henceFor that to happen the pulling force F must exactly equal the frictional force Fk .
Answer:
There are 2.71x10⁴ wavelengths between the source and the screen.
Explanation:
The number of wavelengths (N) can be calculated as follows:
Where:
: is the distance in glass = 2.25 mm
: is the distance in air = 1.50 cm - 0.225 cm = 1.275 cm
: is the wavelength in glass
: is the wavelength in air = 620 nm
To find the wavelength in glass we need to use the following equation:
Where:
: is the refraction index of glass = 1.80
: is the refraction index of air = 1
Hence, the number of wavelengths is:
Therefore, there are 2.71x10⁴ wavelengths between the source and the screen.
I hope it helps you!
