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3 years ago

1. boiling point of water

Physics

1 answer:

melomori [17]3 years ago

5 0

Answer:

what is the question. . .

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If you push an 5 N object 2 m and then push a 10 N object 2 m. Which is TRUE?

Nadya [2.5K]

Answer:

Explanation:

You don't do the same amount of work. The work formula is F*d = W

W = work

F = force

d = the distance moved.

So you do more work when you move the 10N object because the Force (F) has doubled.

4 0

3 years ago

Find the value of 15.0 N in pounds. Use the conversions 1slug=14.59kg and 1ft=0.3048m. Express your answer in pounds to three si

kotykmax [81]

Given the equivalent value to convert the units from kilograms to slug and feet to meters, we will proceed to define the equivalence of the 'Newton' in simplified units, that is,

$1N=1kg\cdot m\cdot s^{-2}$

Then,

$15.0N=15.0kg\cdot m\cdot s^{-2}$

Converting this value to British units we have that

$15N = 15.0kg\cdot m\cdot s^{-2} (\frac{1slug}{14.59kg})(\frac{1ft}{0.3048m})$

$15N = 3.37 slug \cdot ft \cdot s^{-2} (\frac{1 lb \cdot ft^{-1}}{1slug})$

$15N =3.37lb$

Therefore the value of 15.0 N in pounds is 3.37 lb.

6 0

3 years ago

Please help wave number 3

ELEN [110]

Hello!

In Wave 3, there are 40 waves in the wave train. To find the Wavelength of the wave, you'll need to use a ruler to find the measure of the wave in centimeters (I can't really measure the wave because I would be measuring a picture and I wouldn't know if I was accurately measuring the wave), but I would estimate it to be about 2cm long. For the amplitude, I am not certain on what the amplitude would be. I could only manage to find the amount of wave sand the estimated length.

I hope this helps!

7 0

3 years ago

A copper sphere 10 mm in diameter is dropped into a 1-m-deep drum of asphalt. The asphalt has a density of 1150 kg/m3 and a visc

kvasek [131]

Answer:

t = 1964636.542 sec

Explanation:

Given data:

sphere diameter is 10 mm

Density is 1150 kg/m^3

viscosity 105 N s/m^2

We knwo that time taken by sphere can be calculated by following procedure

$\tau = \mu \frac{du}{dy}$

$\frac{F}{A} = \mu \frac{du}{r}$

$\frac{\rho_C -\rho_{asphalt} gv}{2 \pi rL} = 10^5 \frac{du}{r}$

Solving for du

$du = \frac{ (8933 - 1150) 9.81 \frac{4}{3} \pi (10\times 10^{-3})^3}{2\pi \times 1\times 10^5}$

$du = u = 5.09\times 10^{-7}$

$u = \frac{1}{t}$

$t = \frac{1}{5.09\times 10^{-7}} = 1964636.542 sec$

6 0

4 years ago

Solids are usually more dense than: gases liquids plasmas all of the above

vichka [17]

Yes, this is because particles in a solid there are more particles which are touching. They can only vibrate. But particles in a gas are far apart. This is the same for liquids to.

7 0

4 years ago

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