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enyata [817]
3 years ago
13

Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted

ray?
The refracted ray is unpolarized whereas the reflected ray is horizontally polarized.

The refracted ray is unpolarized whereas the reflected ray is vertically polarized.

The refracted ray is horizontally polarized whereas the reflected ray is
unpolarized.

The refracted ray is vertically polarized whereas the reflected ray is unpolarized.

The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.
Physics
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer: The refracted ray is unpolarized whereas the reflected ray is vertically polarized.
 Many light sources like the sun produce waves which are polarized ( randomly). Light which is said to be unpolarized is made up of many waves having all possible directions of polarization.
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dezoksy [38]

Answer:

Explanation:

a ) Slit separation d = .1 x 10⁻³ m

Screen distance D = 4 m

wave length of light  λ = 650 x 10⁻⁹ m

Width of central fringe = λ D / d

= \frac{650\times10^{-9}\times4}{.1\times10^{-3}}

= 26 mm

b ) Distance between 1 st and 2 nd bright fringe will be equal to width of dark fringe which will also be equal to 26 mm

c ) Angular separation between the central maximum and 1 st order maximum will be equal to angular width of fringe which is equal to

λ  / d

= \frac{650\times10^{-9}}{.1\times10^{-3}}

= 6.5 x 10⁻³ radian.

8 0
3 years ago
The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.180 × 10-3 m3. Into this cavity is placed 1.100 × 10-
nikdorinn [45]

Answer:

The answer is "60.74^{\circ}".

Explanation:

Cavity and benzene should be extended in equal quantities.

\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to  (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\

\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\

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3 years ago
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6 0
3 years ago
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In his​ motorboat, Bill Ruhberg travels upstream at top speed to his favorite fishing​ spot, a distance of 120120 ​mi, in 33 hr.
photoshop1234 [79]

Answer:

The rate of the boat in still water is 44 mph and the rate of the current is 4 mph

Explanation:

x​ = the rate of the boat in still water

y​ = the rate of the current.

Distance travelled = 120 mi

Time taken upstream = 3 hr

Time taken downstream = 2.5 hr

Speed = Distance / Time

Speed upstream

\frac{120}{3}=x-y\\\Rightarrow 40=x-y

Speed downstream

\frac{120}{2.5}=x+y\\\Rightarrow 48=x+y

Adding both the equations

48+40=x-y+x+y\\\Rightarrow 88=2x\\\Rightarrow 44=x

40=44-y\\\Rightarrow 40-44=-y\\\Rightarrow y=4

The rate of the boat in still water is <u>44 mph</u> and the rate of the current is <u>4 mph</u>

8 0
3 years ago
A 0.15 kg baseball is hit by a baseball bat. Right before it is hit, the ball’s speed is 30 m/s, and right after it is hit, the
Roman55 [17]

Answer:

Impulse will be 12 kgm/sec

So option (b) will be correct option

Explanation:

We have given mass of the baseball m = 0.15 kg

Ball speed before hit v_1=30m/sec

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We have to find the impulse

We know that impulse is equal; to the change in momentum

So change in momentum = m(v_1-v_2)=0.15(30-(-50))=0.15\times 80=12kgm/sec

So option (b) will be correct option

5 0
3 years ago
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