Answer:
4.44 kN in the opposite direction of acceleration.
Explanation:
Given that, the initial speed of the car is, 
And the mass of the car is, 
The total distance covered by the car before stop, 
And the final speed of the car is, 
Now initial kinetic energy is,

Substitute the value of u and m in the above equation, we get

Now final kinetic energy is,

Substitute the value of v and m in the above equation, we get

Now applying work energy theorem.
Work done= change in kinetic energy
Therefore,

Here, the force is negative because the force and acceleration in the opposite direction.