Answer
given,
velocity of weight = 20 ft/s
height of the leaning tower = 184 ft
velocity of weight
acceleration due to gravity
g = 32 ft/s
a) using equation of motion
v = u + at
v(t) = 20 - g t
v(t) = 20 - 32 t ft/s
b)
at zenith v(t) is equal to zero
v(t) = 20 -32 t
0 = 20 - 32 t
t = 0.625 s
height at instant t = 0.625 s
s = 190.25 m
By definition we have to:
Applied force: It is the external force that acts directly on a body.
Therefore, we can say that if you have an object and push it towards yourself, you are exerting an external force on the object.
This external force was not acting on the object previously, therefore, it is a force that you are applying at that moment.
Answer:
you exert an Applied Force on an object when you pull it towards you
A. Applied Force
<span>We know that the relation between pressure, volume and temperature is constant for ideal gases, so then
P1*V1/T1 = P2*V2/T2
As the volume is held constant, we will have:
P1/T1 = P2/T2
As the pressure is doubled and the temperature in kelvins is 211.15 K, then:
P1/211.15 = 2*P1/T2
T2 = 2*211.15 = 422.3 K
T2 = 422.3 - 273.15 = 149.15
So the final temperature reaches 149.15 ÂşC</span>
Answer:
8.9 seconds
Explanation:
The height of the object at time t is:
y = h + vt − 4.9t²
where h is the initial height, and v is the initial velocity.
Given h = 30 and v = 40:
y = 30 + 40t − 4.9t²
When y = 0:
0 = 30 + 40t − 4.9t²
4.9t² − 40t − 30 = 0
Solving with quadratic formula:
t = [ -(-40) ± √((-40)² − 4(4.9)(-30)) ] / 2(4.9)
t = [ 40 ± √(1600 + 588) ] / 9.8
t = 8.9
It takes 8.9 seconds for the object to land.