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quester [9]
2 years ago
8

The temperature of the air in a valley begins to increase after the sun comes up and heats the valley floor. What will

Physics
1 answer:
tester [92]2 years ago
7 0

Explanation:

I think it will increase a little bit ... just image ... if the temperature is 0, the velocity will be 0 too. because the vibration of atom is so weak and the sound cant progation.

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During a compression test, a cylinder has 40 percent of the specified compression reading. When the technician performs a wet te
Harrizon [31]

Answer:

Worn out piston rings

Explanation:

Here there is increase in the pressure during the wet compression test. Since, the pressure reading from 40 percent of the specified compression reading raised up to 75% of the specified reading.

The cause of the low compression reading could be Worn out piston rings that is allowing the pressured to be released and hence the compression reading is low.

8 0
3 years ago
Hmmm... Who can answer this question?<br><br>How did life begin?<br><br>Just a practice
Schach [20]

Answer:

The earliest known life-forms are putative fossilized microorganisms, found in hydrothermal vent precipitates, that may have lived as early as 4.28 Gya (billion years ago), relatively soon after the oceans formed 4.41 Gya, and not long after the formation of the Earth 4.54 Gya.

Explanation:

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8 0
2 years ago
How much energy is required to increase the temperature of
Basile [38]

Explanation:

Q=msdt

= 2 x 128 x (7-4)

=256 x 3

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6 0
3 years ago
When a 20-V emf is placed across two resistors in series, a current of 2.0 A is present in each of the resistors. When the same
ehidna [41]

Answer:

7.24 ohm

Explanation:

Let R1 and R2 are resistance of two resistors.

Emf=E=20 V

Current,I=2 A

Current,I'=10 A

We have to find the magnitude of the greater of the two resistances.

In series

R=R_1+R_2

V=IR

By using the formula

20=2(R_1+R_2)

R_1+R_2=\frac{20}{2}=10...(1)

In parallel

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}

\frac{1}{R}=\frac{R_2+R_1}{R_1R_2}

R=\frac{R_1R_2}{R_1+R_2}

20=10(\frac{R_1R_2}{R_1+R_2}

2=\frac{R_1R_2}{10}

R_1R_2=20

R_2=\frac{20}{R_1}

Substitute the value

\frac{20}{R_1}+R_1=10

R^2_1+20=10R_1

R^2_1-10R_1+20=0

R_1=\frac{10\pm\sqrt{(-10)^2-4(20)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

R_1=\frac{10\pm 2\sqrt 5}{2}

R_1=\frac{10+2\sqrt 5}{2}=5+\sqrt 5=7.24 ohm

R_1=\frac{10-2\sqrt 5}{2}=2.76 ohm

Substitute the value

R_2=\frac{20}{7.24}=2.76 ohm

R_2=\frac{20}{2.76}=7.24 ohm

Hence, the magnitude of the greater of the two resistance=7.24 ohm

8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!<br> WORTH A LOT OF POINTS!
Shalnov [3]

Answer:

A is your anwser

Explanation:

4 0
3 years ago
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