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beks73 [17]
3 years ago
15

A rectangular site measures 125 feet (frontage) by 256 feet (depth), of which 26 feet is in the public right of way. what is the

gross and net site area? 0.66 acre gross and 0.73 acre net 35,100 square feet gross area and 32,000 square feet net area 38,656 square feet gross area and 32,000 square feet net area 32,000 square feet gross area and 28,750 square feet net area
Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

32,000 square feet gross area and 28,750 square feet net area

Step-by-step explanation:

Given a rectangular site measures 125 feet (frontage) by 256 feet (depth), of which 26 feet is in the public right of way. We have to find the  the gross and net site area.

As, 26 feet width is in the public right of way which excluded in the net area but included in gross area.

For gross area,

Length=125 feet

Width=256 feet

Area=Length\times width=125\times 256=32000 square feet

For net area,

Length=125 feet

Width=256-26=230 feet

Area=Length\times width=125\times 230=28750 square feet

Hence, last option is correct.

The answer is:  32,000 square feet gross area and 28,750 square feet net area

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a quadratic equation has a discriminant of 12. which could be the equation? a.0 = –x2 8x 2 b.0 = 2x2 6x 3 c.0 = –x2 4x 1 d.0 = 4
Norma-Jean [14]

Answer:

Option b which is 2x^2+6x+3=0

Step-by-step explanation:

We have been given the discriminant 12

We have to choose the equation which will satisfy the given discriminant.

We will consider all the given equation one by one

First we will take option a which is -x^2+8x+2=0

Discriminant from the equation we will find by the formula

D=b^2-4ac

Here, a=-1,b=8 and c=2 on substituting the values we will get

D=8^2-4(-1)(2)=72

Hence, option a is incorrect.

Now, we will consider option b which is 2x^2+6x+3=0

Here, a=2,b=6 and c=3 on substituting the values we get

D=(6)^2-4(2)(3)=12

Hence, option b is correct

Therefore, option b is the required answer.

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6 0
3 years ago
HELPPPP!!!
Anuta_ua [19.1K]

Answer:

  A = √29

Step-by-step explanation:

The short of it is that ...

  A² = 2² + 5² = 29

  A = √29

_____

<u>Amplitude</u>

If you expand the second form using the sum-of-angles formula, you get ...

  Asin(ωt +φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Comparing this to the first form, you find ...

  c₂ = 2 = Acos(φ)

  c₁ = 5 = Asin(φ)

The Pythagorean identity can be invoked to simplify the sum of squares:

  (Asin(φ))² + (Acos(φ))² = A²(sin(φ)² +cos(φ)²) = A²·1 = A²

In terms of c₁ and c₂, this is ...

  (c₁)² +(c₂)² = A²

  A = √((c₁)² +(c₂)²) . . . . . . . formula for amplitude

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<u>Phase Shift</u>

We know that tan(φ) = sin(φ)/cos(φ) = (Asin(φ))/(Acos(φ)) = 5/2, so ...

  φ = arctan(c₁/c₂) . . . . . . . formula for phase shift*

  φ = arctan(5/2) ≈ 1.19029 radians

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* remember that c₁ is the coefficient of the cosine term, and c₂ is the coefficient of the sine term.

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