1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crazy boy [7]
3 years ago
10

A 112g serving of ice cream contains 19g of fat. What percentage of the serving is fat?

Physics
1 answer:
zlopas [31]3 years ago
6 0
I think it is 5% hope this helped
You might be interested in
4. Ano ang matinding suliranin ang kakaharapin kapag patuloy ang pagkasira ng
jasenka [17]

Answer:

I think its D

Explanation:

Kasi Pinoy ako

5 0
3 years ago
Read 2 more answers
A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication
koban [17]

Answer:

r = 4.24x10⁴ km.  

     

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km.                           </em>                              

From equation (1), r₁ is:

r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}                            

r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}      

r_{1} = 4.24 \cdot 10^{4} km      

Therefore, the radius of such an orbit is 4.24x10⁴ km.

I hope it helps you!

3 0
3 years ago
According to the photon energy formula, tripling the frequency of the radiation from a monochromatic source will change the ener
Harrizon [31]

Answer:

By a factor of 3

Explanation:

In the photon energy formula , frequency and the energy content have a direct relationship. This means anything that is done to one of the parameters is the same that will be done to the other to have a balance.

In this equation: Energy=plank’s constant * frequency.

Energy is directly proportional to frequency.

3 0
3 years ago
Read 2 more answers
A conductor carrying a current I = 16.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A
Jet001 [13]

To solve this problem we will apply the concepts related to the Magnetic Force, this is given by the product between the current, the body length, the magnetic field and the angle between the force and the magnetic field, mathematically that is,

F = ILBsin \theta

Here,

I = Current

L = Length

B = Magnetic Field

\theta = Angle between Force and Magnetic Field

But \theta = 90\°

F = ILB

Rearranging to find the Magnetic Field,

B = \frac{F}{IL}

Here the force per unit length,

B = \frac{1}{I}\frac{F}{L}

Replacing with our values,

B = \frac{0.130N/m}{16.5}

B = 0.0078T

Therefore the magnitude of the magnetic field in the region through which the current passes is 0.0078T

6 0
3 years ago
A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m th
shepuryov [24]

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

F = ma

a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2}

Now, we can calculate the final speed of the crate at the end of 10.0 m:

v_{f}^{2} = v_{0}^{2} + 2ad_{1}                  

v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s    

For the next 10.5 meters we have frictional force:

F - F_{\mu} = ma

F - \mu mg = ma

So, the acceleration is:

a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2}

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

v_{f}^{2} = v_{0}^{2} + 2ad_{2}  

v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s  

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.  

I hope it helps you!                              

7 0
3 years ago
Other questions:
  • Select all natural hazards that the national weather service measures, predicts, and warns for.
    11·1 answer
  • You are loading a toy dart gun, which has two settings, the more powerful with the spring compressed twice as far as the lower s
    7·1 answer
  • To break a chemical bond, particles need to collide with a certain amount of a]energy. b]atoms. c]molecules. d]chemicals.
    9·1 answer
  • Sam is walking through the park. He hears a police car coming down the street toward him. What happens to the sound of the siren
    13·2 answers
  • A 60-V potential different is applied across a parallel combination of a 10-ohm and 20-ohm resistor. What is the current in the
    6·2 answers
  • If a subway train is moving to the left (has a negative velocity) and then comes to a stop, what is the direction of its acceler
    14·1 answer
  • Which is not a part of physical fitness?
    15·2 answers
  • Which organ allows the exchange of oxygen and carbon dioxide?​
    15·2 answers
  • A block with a mass of 6.0 kg is
    12·1 answer
  • A runner wants to run 12.0 km . Her running pace is 8.2 mi/hr . How many minutes must she run? Express your answer using two sig
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!