Answer:
The average velocity is
and
respectively.
Explanation:
Let's start writing the vertical position equation :

Where distance is measured in meters and time in seconds.
The average velocity is equal to the position variation divided by the time variation.
= Δx / Δt = 
For the first time interval :
t1 = 5 s → t2 = 8 s
The time variation is :

For the position variation we use the vertical position equation :

Δx = x2 - x1 = 1049 m - 251 m = 798 m
The average velocity for this interval is

For the second time interval :
t1 = 4 s → t2 = 9 s


Δx = x2 - x1 = 1495 m - 125 m = 1370 m
And the time variation is t2 - t1 = 9 s - 4 s = 5 s
The average velocity for this interval is :

Finally for the third time interval :
t1 = 1 s → t2 = 7 s
The time variation is t2 - t1 = 7 s - 1 s = 6 s
Then


The position variation is x2 - x1 = 701 m - (-1 m) = 702 m
The average velocity is

Answer:
The answer will be <em>D</em>
Explanation:
I choose answer <em>C</em> and got it wrong on the test. Also Liquid atoms vibrate fast and slide past each other. what answer <em>C </em>shows is a gas.
1) 4min = 4*60 sec = 240 sec
2) Distance = speed times time = 3 * 240 = 720 m
Average acceleration: velocity/time
5/4= 1.25 m/s² Acceleration
Hope I helped :)
Radiation is the only transfer in a vacuum