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ahrayia [7]
3 years ago
12

A group of students put a ford focus in neutral and push the car with 500 N of force to the right, causing the car to travel a d

istance of 10 meters. How much work did the students do on the car?
Physics
1 answer:
SOVA2 [1]3 years ago
4 0

50 meters is the answer

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Calculate the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10. seconds. [Show all wor
bagirrra123 [75]
For this problem, you should be able to differentiate the variables presented from each other in order to substitute them in their corresponding places in the formula or formulas to be utilized in this problem. As for this problem, the only formula to be utilized would be the formula for power which is force multiplied to distance over time or simply have force multiplied to speed since speed is equal to distance over time.

The formula would like this:

Power = force x distance / time                          Power = force x speed

P = 490 N x 2 m / 10 s                                        P = 490 N x (2 m / 10 s)
P = 980 N m / 10 s                                              P = 490 N x 0.2 m / s
P = 98 W                                                             P = 98 W

So the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10 seconds would be 98 watts.
3 0
3 years ago
IMPORTANT 3 QUESTIONS!
Brums [2.3K]

Answer:

7. 20,000,000 mL.

8. 8,000 m.

9. 120,000 secs.

10. 4

Explanation:

7. Determination of the volume in millilitres (mL)

Volume in litre (L) = 20,000 L

Volume in millilitres (mL) =..?

The volume in mL can be obtained as follow:

1 L = 1,000 mL

Therefore,

20,000 L = 20,000 x 1,000 = 20,000,000 mL.

Therefore, 20,000 L is equivalent to 20,000,000 mL.

8. Determination of the distance in metre (m)

Distance in mile = 5 mile

Distance in metre =?

First, we shall convert from mile to kilometre.

This can be done as follow:

1 mile = 1.6 km

Therefore,

5 mile = 5 x 1.6 = 8 km

Finally, we shall convert 8 km to metre (m).

This is illustrated below:

1 km = 1,000 m

Therefore,

8 km = 8 x 1,000 = 8,000 m

Therefore, 5 miles is equivalent to 8,000 m.

9. Determination of the time in seconds.

Time = 400 minutes for 5 days.

First, we shall convert 400 mins to hour.

This is illustrated below:

60 minutes = 1 hour

Therefore,

400 mins = 400/60 = 20/3 hours

The time (hours) is 20/3 hours in 1 day.

Therefore, the time (hours) in 5 days will be = 20/3 x 5 = 100/3 hours.

Next, we shall convert 100/3 hours to minutes.

This is illustrated below:

1 hour = 60 minutes

Therefore,

100/3 hours = 100/3 x 60 = 2000 mins

Finally, we shall convert 2000 mins to seconds.

This is illustrated below:

1 mins = 60 secs

2000 mins = 2000 x 60 = 120,000 secs.

Therefore, the time is 120,000 secs.

10. Determination of the number of significant figures.

To obtain the significant figures of a number, we simply count all the numbers available.

Therefore, the number of significant figures for 9876 is 4.

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