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MAVERICK [17]
2 years ago
9

ANSWER THIS WORKSHEET ALSO I WILL GIVE BRAINIEST

Chemistry
1 answer:
aev [14]2 years ago
4 0

Answer:

5. An element's mass number tells the number of protons in its nucleus.

Atomic

6. Negatively charged particles in an atom are called electrons.

True

7. The cloud model of the atom describes the location of electrons as specific orbits around the nucleus.

Bohr

8. Atoms with the same number of protons but different numbers of neutrons are called isomers.

Isotopes

9. The sum of the protons and neutrons in an atom is called the atomic number.

Mass

10. An object that helps explain ideas about the natural world is called a model.

True

11. Mendeleev arranged his periodic table in order of increasing atomic number.

Mass

12. The rows in the periodic table are called periods.

True

13. Moving across the periodic table from left to right, one finds, in order, metals, then gases, then nonmetals.

Metalloids

14. Another name for a period is a family.

Group

15. On the periodic table, elements in the same column have similar properties.

True

Explanation:

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A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.
MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

A.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

B.

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

C.

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0
3 years ago
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo
RoseWind [281]

Answer:

[SO_3]=0.25M

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\

[SO_3]=0.25M

Best regards!

4 0
2 years ago
Name the following compounds:
timama [110]
A) sodium fluoride
B) rubidium oxide
C) boron trichloride
D) dihydrogen selenide
E) tetraphosphate hexoxide
F) iodine trichloride
6 0
3 years ago
Read 2 more answers
Please help me get the answer to bothe a and b​
neonofarm [45]

Answer:

If a metal and metal solution react, the more reactive metal will displace the less reactive metal from solution. If the metal in solution you start with is formed from a more reactive metal than the metal to be added, no reaction will occur.

3 0
2 years ago
How many grams of NH4ClO4 would dissolve in 250 mL at 30 C
baherus [9]
Ammonium perchlorate appears as a white, crystalline solid or powder. Classified as a division 1.1 explosive if powdered into particles smaller than 15 microns in diameter or if powdered into larger particles but thoroughly dried. Does not readily burn, but will burn if contaminated by combustible material. May explode under prolonged exposure to heat or fire. Used to make rocket propellants, explosives, pyrotechnics, as an etching and engraving agent, and in analytical chemistry.
8 0
3 years ago
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