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deff fn [24]
3 years ago
15

Which of the following sources is considered to be most reliable for scientific

Chemistry
1 answer:
Anarel [89]3 years ago
8 0

Answer:

The answer is D

Explanation:

Pls mark as brainliest

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Which of the following is not a valid set of quantum numbers
ASHA 777 [7]
I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or 

<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.

For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.

The other three sets are valid and can correctly describe an electron.

3 0
3 years ago
Read 2 more answers
If a can of soup 150 g mass and 0.75g/ cm^3 density what’s the volume
Liula [17]

Answer:

<h3>The answer is 200 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}\\

From the question

mass = 150 g

density = 0.75 g/cm³

We have

volume =  \frac{150}{0.75}  \\

We have the final answer as

<h3>200 cm³</h3>

Hope this helps you

8 0
3 years ago
While conducting a lab experiment, Ali calculated that 1.20 E6 Joules of heat were needed to melt 18.5 kilograms of an unknown s
nordsb [41]

Answer:

Latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

Explanation:

Latent heat of fusion denotes amount of energy (heat) per unit mass required to melt a solid material at constant temperature and pressure i.e. at it's melting point

Here amount of heat required = 1.20\times 10^{6}J

Mass of unknown substance being melted = 18.5 kg

So, latent heat of fusion of the substance = (required heat energy to melt)/(mass of the unknown substance) = \frac{1.20\times 10^{6}}{18.5}J/kg=6.49\times 10^{4}J/kg

So, latent heat of fusion of the substance is 6.49\times 10^{4}J/kg

7 0
3 years ago
An aqueous NaClNaCl solution is made using 111 gg of NaClNaCl diluted to a total solution volume of 1.20 LL .Calculate the molal
Aliun [14]

Answer:

The answer to your question is m = 1.6

Explanation:

Data

mass of NaCl = 111 g

volume of water = 1.2 L

Molality = ?

Formula

Molality = number of moles / volume (L)

Process

1.- Calculate the moles of NaCl

Molecular mass = 23 + 35.5 = 58.5 g

                          1 mol of ------------------- 58.5 g

                          x           -------------------- 111 g

                          x = (111 x 1) / 58.5

                          x = 1.897 moles of NaCl

2.- Calculate the mass of water

density of water = 997 kg/m³

mass = volume x density

mass = 0.0012 x 997

mass = 1.19 kg

3.- Calculate molality

m = 1.897/1.19

m = 1.6

   

7 0
3 years ago
Particles are close to each other but can still slide past each other
scoray [572]

It is True. Hope this helped.

8 0
3 years ago
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