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masya89 [10]
2 years ago
7

Guys help please!! any five effects of heat!!​

Chemistry
1 answer:
Bogdan [553]2 years ago
3 0

{\huge {\underline {\underline {\bold {\blue{Effects \:  of \:  Heat}}}}}}

  • <em>Expansion </em><em>of </em><em>particles</em><em> </em><em>of</em><em> </em><em>substances.</em><em> </em>
  • <em>Increase</em><em> </em><em>in </em><em>temperature</em><em>.</em>
  • <em>Change</em><em> </em><em>in </em><em>state</em><em>.</em>
  • <em>Change</em><em> </em><em>in </em><em>physical</em><em> </em><em>property</em>
  • <em>It </em><em>may </em><em>bring</em><em> </em><em>out </em><em>chemical</em><em> </em><em>changes</em><em>.</em>

__________________________________

\tt\underline\orange{hope \: it \: helps}

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Give the nuclear symbol for the isotope of potassium for which a=40?
KATRIN_1 [288]

<span>nuclear symbol consists of three parts: 1. the symbol of the element; 2. the atomic number of the element;3. the mass of the element. for the above problem, the symbol for potassium is k. it's atomic number is 40. the number of protons is 19. so we denote this in the following nuclear symbol; 40 k 19</span>

4 0
3 years ago
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What is the mass of oxygen in 3.34 g of potassium permanganate?
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Answer:

1.35 g

Explanation:

Data Given:

mass of Potassium Permagnate (KMnO₄) = 3.34 g

Mass of Oxygen: ?

Solution:

First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)

So,

Molar Mass of KMnO₄ = 39 + 55 + 4(16)

Molar Mass of KMnO₄ = 158 g/mol

Calculate the mole percent composition of  Oxygen in Potassium Permagnate (KMnO₄).

Mass contributed by Oxygen (O) = 4 (16) = 64 g

Since the percentage of compound is 100

So,

                        Percent of Oxygen (O) = 64 / 158 x 100

                        Percent of Oxygen (O) = 40.5 %

It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.

So,

for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be

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5 0
3 years ago
In uncompetitive inhibition, the inhibitor can bind to the enzyme only after the substrate binds first. (T/F)
Veronika [31]

Answer:

True

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This inhibition is called uncompetitive because the inhibitor does not compete with the substrate to bind on the active site of the enzyme.

Therefore, in an uncompetitive inhibition, the inhibitor molecule can not bind on the active site of the enzyme directly. The inhibitor can only bind to the enzyme-substrate complex formed.

       

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Vinil7 [7]
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Answer: this is the explanation

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