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masya89 [10]
2 years ago
7

Guys help please!! any five effects of heat!!​

Chemistry
1 answer:
Bogdan [553]2 years ago
3 0

{\huge {\underline {\underline {\bold {\blue{Effects \:  of \:  Heat}}}}}}

  • <em>Expansion </em><em>of </em><em>particles</em><em> </em><em>of</em><em> </em><em>substances.</em><em> </em>
  • <em>Increase</em><em> </em><em>in </em><em>temperature</em><em>.</em>
  • <em>Change</em><em> </em><em>in </em><em>state</em><em>.</em>
  • <em>Change</em><em> </em><em>in </em><em>physical</em><em> </em><em>property</em>
  • <em>It </em><em>may </em><em>bring</em><em> </em><em>out </em><em>chemical</em><em> </em><em>changes</em><em>.</em>

__________________________________

\tt\underline\orange{hope \: it \: helps}

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Answer:

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I don't know if this is what you wanted or not sorry if it isn't

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3 years ago
The ksp of yttrium fluoride, yf3, is 8.62 × 10-21. calculate the molar solubility of this compound.
motikmotik

Answer:

The molar solubility of YF₃ is 4.23 × 10⁻⁶ M.

Explanation:

In order to calculate the molar solubility of YF₃ we will use an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and we complete each row with the concentration of change of concentration. Let's consider the solubilization of YF₃.

       YF₃(s) ⇄ Y³⁺(aq) + 3 F⁻(aq)

I                       0               0

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E                       S              3S

The solubility product (Ksp) is:

Ksp = [Y³⁺].[F⁻]³= S . (3S)³ = 27 S⁴

S=\sqrt[4]{Ksp/27} =\sqrt[4]{8.62 \times 10^{-21}  /27}=4.23 \times 10^{-6}M

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A chemistry graduate student is studying the rate of this reaction: H2CO3(aq) →H2O(aq)+CO2(aq)
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