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Scorpion4ik [409]

3 years ago

5

If a laser beam is shot straight up from the bottom of a pool so that it intersects the pools surface in a perpendicular fashion

, what will the angle of refraction be in the air?
A) 0
B)45
C)90
D)This cannot ve measured

1 answer:

Nat2105 [25]3 years ago

6 0

A. the change in medium cannot affect the angle if the angle is perpendicular.

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An airplane travels 2800 km at a speed of 700 km/h, decreases its speed to 500 km/h for the next 1500 km and travels the last 10

Dafna11 [192]

Answer:

he average speed for the airplane is 558 km/hr

Explanati

6 0

3 years ago

1. The planet Jupiter completes a revolution of the sun in 11.5 years. Express it in seconds. Given that one year= 3.154 × 10^7

xenn [34]

Answer:

The planet Jupiter completes one revolution of the sun in 362710000 seconds. Long time, right?

Explanation:

3.154x10^7=3.154x10000000=31540000

11.5x31540000=362710000

7 0

2 years ago

A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its a

pentagon [3]

Answer:

Explanation:

Given dish width= 48ft

Depth = 4ft

Using equation of a parabola

x²= 4py

48² = 4p 4

4p = 576

P= 144ft

Thus the the receiver should be placed 144ft from t the vertex

7 0

3 years ago

A raindrop of mass 0.5 * 10^-4 kg is falling verctically under the influence of gravity. The air drag on the raindrop is fdrag =

Elina [12.6K]

Answer:

The displacement of the air drop after 3 second is 18.27 m.

Explanation:

Mass of the rain drop = m = $0.5\times 10^{-4} kg$

Weight of the rain drop = W

Duration of time = t = 3 seconds

$W=m\times g$

Drag force on rain drop = $D=0.2\times 10^{-5} v^2$

$W=0.5\times 10^{-4} kg\time 10 m/s^2=0.5\times 10^{-3} N$

Motion of the rain drop:

$F=m\times a$

Net force on the rain drop , F= W - D

$W-D=m\times a$

$0.5\times 10^{-3} N-0.2\times 10^{-5} v^2=0.5\times 10^{-4} kg\times a$

$0.5\times 10^{-3} kg m/s^2-0.2\times 10^{-5} v^2=0.5\times 10^{-4} kg\times \frac{v}{t}$

$0.006v^2+0.05v-1.5=0$

v = 12.18 m/s

Initial velocity of the rain drop = u = 0 (since, it is starting from rest)

v=u+at (First equation of motion)

$12.18 m/s=0m/s+a\times 3 s$

$a=4.06 m/s^2$

$s=ut+\frac{1}{2}at^2$ (second equation of motion)

$s=0\times 3s+\frac{1}{2}\times 4.06m/s^2\times (3 s)^2$

s = 18.27 m

The displacement of the air drop after 3 second is 18.27 m.

6 0

3 years ago

Two speakers hang from racks placed in an open field. When sound of the same frequency comes from both speakers, no sound is hea

Vanyuwa [196]

Answer:

Explanation:

Wgen the sound is emitting from two speakers, the sound waves interfere each other. the locations at which the destructive interference occurs, we get no sound and the locations where constructive interference occurs, the sound occurs at that locations.

8 0

3 years ago