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antiseptic1488 [7]
3 years ago
10

Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force

of 5.2 N is applied.
Physics
2 answers:
kkurt [141]3 years ago
7 0
Formula for feild strength= F/q
q=7.0^10-5 coulombs
F=5.2 N
E=5.2 / 7.0^10-5
E=
Evgesh-ka [11]3 years ago
5 0
E = F/q

   = 5.2 N / (7* 10⁻⁵) C

   = 7.429 * 10⁴ N/C
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A square plate of copper with 50.0-cm sides has no net charge and is placed in a region of a uniform electric field of 80.0 kN/C
torisob [31]

Answer:

σ = ±708 nC/m²

Q = ±177 nC

Explanation:

given data

Side of copper plate L = 50 cm

Electric field, E = 80 kN/C

solution

we get here Charge density,σ that is express as

σ = E x ε₀         ....................1

here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²

so put value in eq1we get

σ = 80 x 10³ x 8.85 x 10⁻¹²

σ = 708 x 10⁻⁹ C/m²

σ = 708 nC/m²

and

now we get here total change on each faces

Q = σ  A    ...............2

Q = 708 x 10⁻⁹ x (0.50)²

Q = 177 nC

3 0
3 years ago
IF YOUR GOOD AT SCIENCE THEN PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST
MakcuM [25]

Answer:

A: Copper is a good conductor

Explanation:

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Fun fact, sinc humans are also super bendy and essentially big sacs of all things wet and watery, we're considered to also be excellent conductors. We also have very intricate circuitry and a lot of natural electricity so basically, we were made for it, especially since the body already used little bits of electricity to function.

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Once broken into parts curved motion can be worked as ________________ problems along both axes.
vovikov84 [41]

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4 years ago
Which label belongs in the area marked X? Current Magnetic field Solenoid Force on wire
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<u>Magnetic Field</u>

8 0
3 years ago
Read 2 more answers
A barge floating in fresh water (p = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H
Karolina [17]

Answer:

a) \Delta m = 330000\,kg, b) h = 1.268\,m

Explanation:

a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:

\Delta m \cdot g = \rho_{w}\cdot g \cdot \Delta V

\Delta m = \rho_{w}\cdot \Delta V

\Delta m = \left(1000\,\frac{kg}{m^{3}} \right)\cdot (550\,m^{2})\cdot (1.05\,m-0.45\,m)

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b) The submersion height is found by using the equation derived previously:

\Delta m = \rho_{w}\cdot \Delta V

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The final submersion height is:

h = 1.268\,m

4 0
3 years ago
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