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SVEN [57.7K]
4 years ago
12

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground

Physics
1 answer:
Setler79 [48]4 years ago
6 0
They will both hit the ground at the same time because gravitational acceleration for all objects is the same.
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Consider two children sitting on a merry-go-round, with one closer to the outer edge and one closer to the center. show answer N
dolphi86 [110]

Answer:

They both have the same angular speed.

Explanation:

The mathematical formula for angular speed is:

w=\frac{2\pi}{T}

where w is angular speed, 2\pi is a constant, and T is the period (the time it takes the marry-go-round to complete a lap).

What we can see from the formula is that, since the 2\pi does not change its value, the angular speed depends only on the period T.

In this case for both the children closer to the outher edge and for the children closer to the center, the time to complete a lap is the same, because the time does not depend on where they are sitting in the marry go round. This means that the period for both is the same.

Thus, since the period for both is the same, the angular speed given by

w=\frac{2\pi}{T} will also be the same

4 0
4 years ago
Two very small spheres are initially neutral and separated by a distance of 0.30 m. Suppose that 2.50 1013 electrons are removed
quester [9]

Answer:

F = - 1,598 10⁻³ N

Explanation:

Electic strength is given by Coulomb's law

          F = k q₁ q₂  / r²

Where k is the Coulomb constant that is worth 8.99 10⁸ N m²/C², q₁ and q₂ are the charges and r is the distance that separates the electric charges

In this case the charge of the two spheres is the same and of a different sign since when you remove the charge of a sphere that was initially neutral, it is left with that charge removed but of the opposite sign

       q₁ = q₂ = 2.50 10¹³ electrons = 2.50 10¹³ 1.6 10⁻¹⁹

       q₀ = 4.0 10⁻⁶ C

Let's calculate

       F = - 8.99 10⁸ (4.0 10⁻⁶)² / 0.30²

       F = - 1,598 10⁻³ N

4 0
4 years ago
Mary spots Bill approaching the dorm at a constant rate of 2.00 m/s on the walkway that passes directly beneath Mary's window, 1
vagabundo [1.1K]

Answer:

Mary will have to wait for 63.2 seconds

Explanation:

Time required for the apple to drop from a height of 17.0 m above the ground to 1.65 m above the ground is given by the formula below:

t = √2h/g  where h is height through which the object falls, g is acceleration due to gravity

h = 17.0 - 1.65 = 15.35 m

g = 9.8 m/s²

t = √(2 * 15.35/9.8)

t = 1.77 s or approximately 1.8 s

Time taken for bill to get to the point below Mary's window is given below;

time taken = distance/velocity

distance = 130 m; velocity = 2.0 m/s

time taken by Bill = 130/2.0 = 65 s

Therefore, Mary will have to wait for (65 - 1.8) s = 63.2 seconds

4 0
3 years ago
Anyone please help thank you
Thepotemich [5.8K]

Answer:

A) earth

B) live

C) live

D) earth

Explanation:

hope i help

4 0
2 years ago
Find the speed of a bicyclist who took an hour and a half to travel 10km
Natalija [7]

distance = 10km

time = 1 1/2 = 3/2 hours

speed = distance/time = 10 / 3/2 = 20/3 = 6.67 Km/h

7 0
3 years ago
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